Question

我有以下JSON对象，其中存储了所有数据。

[{"id":1,"CoinValue":"0.01","Count":82,"CoinWeight":76},
{"id":2,"CoinValue":"0.02","Count":86,"CoinWeight":18},
{"id":3,"CoinValue":"0.05","Count":29,"CoinWeight":42},
{"id":4,"CoinValue":"0.1","Count":35,"CoinWeight":90},
{"id":5,"CoinValue":"0.2","Count":23,"CoinWeight":3},
{"id":30,"CoinValue":"0.5","Count":41,"CoinWeight":36}]

我希望获得每条记录的CoinValue和Count，以便在Google图表中显示。目前，我有一个视图在Coin控制器中调用一个名为Data的方法来接收数据，但是我无法使其工作。

CoinController：

    public ActionResult Data()
    {
        //Read Json object
        var fileContents = System.IO.File.ReadAllText(@"H:\EasyAsPiMVC\EasyAsPiMVC\App_Data\MOCK_DATA.json");

        //not sure how to properly pass this data to the view 

        return Json(fileContents);
    }

用于处理和显示数据的Javascript

<script type="text/javascript">
$(document).ready(function () {
    $.ajax({
        type: 'POST',
        dataType: "Json",
        contentType: "application/json",
        url: '@Url.Action("Data", "Coin")',
        success: function (result) {
            google.charts.load('current', {
                'packages': ['corechart']
            });
            google.charts.setOnLoadCallback(function () {
                drawChart(result);
            });
        }
    });

    function drawChart(result) {
        var data = new google.visualization.DataTable();
        data.addColumn("string", "CoinValue"); //might have to be changed
        data.addColumn("number", "Count");
        var dataArray = [];
        $.each(result, function (i, obj) {
            dataArray.push([obj.CoinValue, obj.Count]);
        });
        data.addRows(dataArray);

        var piechart_options = {
            title: 'Coin Tracker Piechart',
            width: 400,
            height: 300
        };

        var piechart = new google.visualization.PieChart(document.getElementById('piechart_div'));
        piechart.draw(data, piechart_options);

        var barchart_options = {
            title: 'Coin Tracker barchart',
            width: 400,
            height: 300,
            legend: 'none'
        };

        var barchart = new google.visualization.BarChart(document.getElementById('barchart_div'));
        barchart.draw(data, barchart_options);
    }
});
</script>

我是一个编程菜鸟，现在已经有一天没想到这个了。我做了大量的研究，但我似乎无法做到这一点。

Answer 1

composer.json方法为您提供ReadAllText，即文件的内容。您需要将其反序列化为string个对象的列表。您的客户端代码需要一组对象，每个对象都具有Coin和CoinValue属性。所以你需要返回那个json数组。

以下是使用JSON.NET

的方法

Count

如何从MVC中的JSON对象中获取数据

1 个答案: