Question

我正在尝试使用带有谓词的表达式来显示每个父节点的子节点（练习看起来很愚蠢，因为这是测试数据：最终解决方案必须从其他xml文件中提取数据）。

数据样本如下：

<Schools>
<School>
<name>St John's</name>
<AcademicYear year = "2017"></AcademicYear>
<Subject>English</Subject>
<Subject>Geography</Subject>
<Subject>Maths</Subject>
<AcademicYear year = "2016"></AcademicYear>
<Subject>Maths</Subject>
<Subject>Textiles</Subject>
<Subject>English</Subject>
<AcademicYear year = "2015"></AcademicYear>
<Subject>History</Subject>
<Subject>French</Subject>
<Subject>Spanish</Subject>
</School>

<School>
<name>Marsh Academy</name>
<AcademicYear year = "2017"></AcademicYear>
<Subject>Science</Subject>
<Subject>Geography</Subject>
<Subject>Computer science</Subject>
<AcademicYear year = "2016"></AcademicYear>
<Subject>English</Subject>
<Subject>History</Subject>
<Subject>Maths</Subject>
<AcademicYear year = "2015"></AcademicYear>
<Subject>French</Subject>
<Subject>Geography</Subject>
<Subject>Art</Subject>
</School>

</Schools>

查询如下：

<Schools>
{for $School in doc("test.xml")/Schools/School
return
<School>
  <Name>
  {$School/name}
  </Name>
  {for $i in doc("test.xml")/Schools/[School = $School]/AcademicYear
  return
  <AcademicYear>
    {$i/@year}
    <subject><teacher></teacher><scale></scale></subject>
  </AcademicYear>}
   </School>}
</Schools>

错误显示为“预期的节点，找到的数组”与第8行有关。我尝试了两个for循环，只是将一个表达式放在学年标签内，如下所示

{doc（“test.xml”）/ Schools / [School = $ School] / AcademicYear / @ year}

抱歉 - 我确信这很简单。我是初学者！

Answer 1

谓词前面没有子节点。

选择School元素时，将其移出谓词之外作为从Schools元素中选择的子节点，然后在谓词过滤器内部，引用当前School元素与.：

for $i in doc("test.xml")/Schools/School[. = $School]/AcademicYear

但是，如果您正在迭代同一文档中的元素，为什么不使用已经选择的$School：

for $i in $School/AcademicYear

带谓词的XQuery表达式

1 个答案: