Question

我有一个定义函数的脚本，然后运行它

from datetime import timedelta

def foo():
    return timedelta(days=2)


print(foo())

如果我打开一个shell并运行脚本，一切运行正常：

./manage.py shell

In [1]: %run web/the_script.py # Using Ipython
2 days, 0:00:00

但是当我将脚本作为./manage.py shell的输入运行时（我希望将脚本作为cron作业运行），它会像这样失败：

./manage.py shell < the_script.py 
Traceback (most recent call last):
  File "./manage.py", line 22, in <module>
    execute_from_command_line(sys.argv)
  File "/home/satan/Development/envs/p3_env/lib/python3.5/site-packages/django/core/management/__init__.py", line 363, in execute_from_command_line
    utility.execute()
  File "/home/satan/Development/envs/p3_env/lib/python3.5/site-packages/django/core/management/__init__.py", line 355, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/home/satan/Development/envs/p3_env/lib/python3.5/site-packages/django/core/management/base.py", line 283, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/home/satan/Development/envs/p3_env/lib/python3.5/site-packages/django/core/management/base.py", line 330, in execute
    output = self.handle(*args, **options)
  File "/home/satan/Development/envs/p3_env/lib/python3.5/site-packages/django/core/management/commands/shell.py", line 101, in handle
    exec(sys.stdin.read())
  File "<string>", line 8, in <module>
  File "<string>", line 5, in foo
NameError: name 'timedelta' is not defined

有人可以解释一下发生了什么吗？

Answer 1

我之前看过这个问题，它有时只会从脚本执行第一行（或第一个函数）。这主要是因为在整个脚本执行过程中函数没有保持定义（或者是你的情况下的导入）。

试试这个：

./manage.py shell <<EOF\ execfile(the_script.py') \EOF

或者，如果它是Python 3 +

$ ./manage.py shell
...

>>> exec(open('./myscript.py').read())

不太好的解决方案：

echo 'import the_script' | python manage.py shell

当送到manage.py时，无法在脚本中导入模块

1 个答案: