Question

我很难找到一个好的解决方案或之前的问题，因为它难以用语言表达，但我在这里有一个json对象：

{

    "type":"template",
    "customStyle":false,
    "preheaderVisible":true,
    "titleText":"Email Template",
    "mainBlocks":{
        "type":"blocks",
        "blocks":[
            {
                "type":"singleArticleBlock",
                "image":{
                    "type":"image",
                    "src":"/template/image/logo-large.png",
                    "url":"http://example.com/",
                    "alt":""
                },
                "longText":"\n <p>Far far away, behind the word mountains, far from the countries <a href=\"\">Vokalia and Consonantia</a>, there live the blind texts. Separated they live in Bookmarksgrove right at the coast of the Semantics, a large language ocean. A small river named Duden flows by their place and supplies it with the necessary regelialia.</p>\n ",
                "buttonLink":{
                    "type":"link",
                    "text":"BUTTON",
                    "url":"http://example.com/"
                }
            },
            {
                "type":"tripleArticleBlock",
                "leftImage":{
                    "type":"image",
                    "src":"/template/image/logo-small.png",
                    "url":"http://example.com/",
                    "alt":""
                },
                "leftLongText":"\n <p>Far far away, behind the word mountains, far from the countries <a href=\"\">Vokalia and Consonantia</a>, there live the blind texts. </p>\n ",
                "leftButtonLink":{
                    "type":"buttonLink",
                    "text":"BUTTON",
                    "url":"http://example.com/"
                },
                "middleImage":{
                    "type":"image",
                    "src":"/template/image/logo-small.png",
                    "url":"http://example.com/",
                    "alt":""
                },
                "middleLongText":"\n <p>Far far away, behind the word mountains, far from the countries <a href=\"\">Vokalia and Consonantia</a>, there live the blind texts. </p>\n ",
                "middleButtonLink":{
                    "type":"buttonLink",
                    "text":"BUTTON",
                    "url":"http://example.com/"
                },
                "rightImage":{
                    "type":"image",
                    "src":"",
                    "url":"http://example.com/",
                    "alt":""
                },
                "rightLongText":"\n <p>Far far away, behind the word mountains, far from the countries <a href=\"\">Vokalia and Consonantia</a>, there live the blind texts. </p>\n ",
                "rightButtonLink":{
                    "type":"buttonLink",
                    "text":"BUTTON",
                    "url":"http://example.com/"
                }
            },
        ]
    }
}

我需要获取每个url属性，无论它的嵌套深度或子对象如何。因此它可能是image或leftButtonLink的网址并在任何深度。我认为那里必须是一个简单的＆＃34;给我所有的道具叫做x＆＃34;功能。什么是在php中最有效的方法？

Answer 1

这是未经测试的，尝试这样的事情

$data = json_decode($jsondata, true);
$urls = array();
r_search($data);

function r_search($array) {
  global $urls;
  foreach ($array as $key => $value) {
    if (is_array($value)) {
      r_search($value);
    } else if ($key === 'url') {
      $urls[] = $value;
    }
  }
}

没有全局变量可能还有更好的方法。做一些搜索递归数组搜索。

Answer 2

array_walk_recursive应该可以很好地解决这个问题。

$data = json_decode($json, true);
$urls = [];
array_walk_recursive($data, function($value, $key) use (&$urls) {
    if ($key == 'url') $urls[] = $value;
});

确保通过设置json_decode的第二个参数来解码到数组而不是对象。

但是，如果重要的话，这不会告诉您的URL是什么。（例如image，leftButtonLink等等。这只是一个简单的＃34;给我所有的道具叫x＆＃34;功能

如何深入搜索php对象并拉出某个属性的所有实例？

2 个答案: