Question

我有这个网站，我想点击“登录”按钮。 https://www.paycomonline.net/v4/ee/web.php/app/login

我玩了一些功能但没有成功（我不是网络编码器/程序员）。

创建按钮的行是：
<button type="submit" name="submit" id="btnSubmit" class=" waves-effect waves-light" aria-label="Log In">Log In</button>

任何人都可以帮助我吗？提前谢谢！

表格的完整代码为：

<form role="form" action="" method="post" >
 <div class="cardContainer shadow padding marginBottom formGroup row">
  <div class="row formRowStandard ">
   <label class="standard" for="txtlogin"><span class="required">*</span>Username</label>
    <div class="formLine">
     <div class="formControl fbControl">
      <input type="text" name="username" type="text" name="username" id="txtlogin" size="25" maxlength="75" placeholder="Username" class=" inputBoxBorder" aria-label="Username" required="required" value="">
     </div>
    </div>
   </div>
   <div class="row formRowStandard ">
    <label class="standard" for="txtpass"><span class="required">*</span>Password</label>
     <div class="formLine">
      <div class="formControl fbControl"><input type="password" name="userpass" type="password" name="userpass" id="txtpass" size="25" maxlength="20" placeholder="Password" autocomplete="off" class=" checkForCapslock inputBoxBorder" aria-label="Password" required="required" value="">
     </div>
    </div>
   </div>
   <div class="row formRowStandard "><label class="standard" for="userpinid"><span class="required">*</span>Last 4 digits of SSN</label>
    <div class="formLine">
     <div class="formControl fbControl"><input type="password" name="userpin" type="password" name="userpin" id="userpinid" size="25" maxlength="4" placeholder="Last 4 digits of SSN" class=" inputBoxBorder" aria-label="Last 4 digits of SSN" required="required" value="">
    </div>
   </div>
  </div>
  <div class="row formRowStandard ">
   <div class="formLine">
    <div ><button type="submit" name="submit" type="submit" name="submit" id="btnSubmit" class=" waves-effect waves-light" aria-label="Log In">Log In</button>
    </div>
   </div>
  </div>
 </div>
</form>

Answer 1

实际上可以使用它：

document.getElementById("btnSubmit").click();

Greasemonkey / Tampermonkey sript点击按钮

1 个答案: