Question

当我尝试获取与category表有关系的所有记录时，category_definition_id是搜索输入，我无法访问sub方法中的$ request-＆gt; category变量。它在Laravel 5.5中。有什么想法吗？

public function jobopenings(Request $request)
{
  $category_definitions = Category_definition::all();
  $skill_definitions = Skill_definition::all();

  $ads = new Ad;

  // Search for a user based on their name.
  if ($request->has('category')) {

    $ads = $ads->whereHas('categories', function($query){
        $query->where('category_definition_id', $request->category);
      });
  }

  $ads = $ads->where('type','1')->orderBy('created_at','desc')->paginate(15);

    return View::make('jobs')
    ->with('ads', $ads)
    ->with('category_definitions',$category_definitions)
    ->with('skill_definitions', $skill_definitions)
    ->with('ad_type','1');
}

Answer 1

您必须使用use($request)声明它：

$ads = $ads->whereHas('categories', function($query) use ($request) {
           $query->where('category_definition_id', $request->category);
       });

Answer 2

添加use子句：

$ads = $ads->whereHas('categories', function($query) use ($request) {
        $query->where('category_definition_id', $request->category);
    });
}

未定义的变量：sub方法中的请求

2 个答案: