分组从子查询返回的数据

时间:2017-12-01 12:55:59

标签: sql

我有以下查询,它根据帐户类型返回值:

SELECT COALESCE(B.classdescription, 'S CORPORATION') AS "DESCRIPTION", 
       Count(*)                                      AS "NUMBEROFACCOUNTS", 
       Sum(Cast(current_cert_shares AS DECIMAL(20, 3))) 
       + Sum(Cast(current_book_shares AS DECIMAL(20, 3))) 
       + Sum(Cast(dr_curr_shares AS DECIMAL(20, 3))) AS TOTAL 
FROM   testtable1 A 
       LEFT JOIN testtable2 B 
              ON A.class_code = B.classcode 
WHERE  conumber = 00000 
       AND A.special_account_code NOT IN( 001 ) 
GROUP  BY B.classdescription, 
          A.class_code 

要求是仅显示类代码'001','002','003','004','005'的数据。其余类别代码(006至010)的数据需要整理并显示为描述“OTHER”,其中包括NUMBEROFACCOUNTS和TOTAL的总和,用于类代码006至010.

以下图片将显示所需的视图。无需计算%OS值:

Data Table

enter image description here

如何通过单个查询实现此视图?

“其他”的总值可以从中得出:

SELECT Sum(a.numberofaccounts) AS other, 
       Sum(a.total)            AS othertotal 
FROM   ( 
             SELECT    COALESCE(b.classdescription, 'S CORPORATION') AS "DESCRIPTION",
                       Count(*)                                      AS "NUMBEROFACCOUNTS",
                       Sum(Cast(current_cert_shares AS DECIMAL(20,3))) +
                       Sum(Cast(current_book_shares AS DECIMAL(20,3))) +
                       Sum(Cast(dr_curr_shares AS DECIMAL(20,3))) AS total
             FROM      accountmaster A 
             LEFT JOIN classcodes B 
             ON        a.class_code = b.classcode 
             WHERE     conumber = 11991 
             AND       a.special_account_code NOT IN(02) --and 
                       class_code NOT             IN( '042', '010', '012', '022', '011') 
             GROUP BY  b.classdescription, 
                       a.class_code ) a

0 个答案:

没有答案
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