说我有员工的对象
Employee employee = new Employee();
employeee.setId(1);
employee.setName("stack");
我希望将其转换为格式低于
的格式这是我想要的xml fomat
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http:/someurl" xmlns:bas="http://someurl" xmlns:req="http://someurl" xmlns:sch="http://someurl">
<soapenv:Body>
<ns1:employeeReturn xmlns:ns1="someurl">
<ns2:result xmlns:ns2="someurl">
<ns3:resultCode xmlns:ns3="someurl">00000000</ns3:resultCode>
<ns4:resultMessage xmlns:ns4="someurl">Success</ns4:resultMessage>
</ns2:result>
<ns5:resultList xmlns:ns5="http://someurl">
<ns1:item>
<ns6:resultCode xmlns:ns6="http://someurl">00000000</ns6:resultCode>
</ns1:item>
</ns5:resultList>
<ns7:subResponseInfos xmlns:ns7="http://someurl">
<ns1:item>
<ns8:effectiveEndTime xmlns:ns8="http://someurl">20361231170000</ns8:effectiveEndTime>
</ns1:item>
</ns1:employeeReturn >
</soapenv:Body>
</soapenv:Envelope>
我尝试按如下方式创建肥皂信息
SOAPMessage soapMessage = messageFactory.createMessage();
SOAPPart soapPart = soapMessage.getSOAPPart();
SOAPEnvelope envelope = soapPart.getEnvelope();
SOAPBody body = envelope.getBody();
envelope.addNamespaceDeclaration("xsi", "http://url");
SOAPBodyElement element0 = body.addBodyElement(
envelope.createName("employeereturn", "ns1", "http://url"));
SOAPElement element1 = element0.addChildElement(
body.addBodyElement(envelope.createName("result", "ns2", "http://url")));
SOAPElement element2 = element1.addChildElement(body.addBodyElement(envelope.createName("resultCode", "ns3", "http://url"))).addTextNode("00000");
element1.addChildElement(body.addBodyElement(envelope.createName("resultMessage", "ns4", "http://url"))).addTextNode("success");
SOAPElement element3 = element0.addChildElement(
body.addBodyElement(envelope.createName("resultList", "ns5", "http://url")));
但随着您的员工对象变大并且有一些嵌套对象,将很难维护代码