Question

我正在使用Xammp服务器，我在下面编写了创建表的php代码，这给了我语法错误

<?php
$con=@mysqli_connect('localhost', 'root', '', 'shop');

create table customer(
        cust_id int primary key,
        name varchar(255) ,
        Email varchar(255) 
);
?>

错误

语法错误，第6行C：\ xampp \ htdocs \ shop.php中的意外T_STRING

Answer 1

您应该将查询分配到变量中。

$sql = "create table customer(
        cust_id int primary key,
        name varchar(255) ,
        Email varchar(255) 
        )";

Answer 2

你需要将create table语法设置为变量，然后用它来执行 mysqli_query

<?php
$con=@mysqli_connect('localhost', 'root', '', 'shop');

$sql = "create table customer(
    cust_id int primary key,
    name varchar(255) ,
    Email varchar(255) 
);";

if(mysqli_query($con, $sql)){  
     echo "Table created successfully";  
} else {  
    echo "Table is not created successfully ";  
}  
?>

本教程https://www.tutorialspoint.com/mysqli/mysqli_create_tables.htm

语法错误，第6行的C：\ xampp \ htdocs \ shop.php中的意外T_STRING

2 个答案: