Question

我知道这是一个简单的问题，但为什么我会多次获得相同的记录？我尝试使用dd($data)，它向我展示了多个相同的记录。我做错了什么？

profile.blade.php

 @foreach($data as $value) 
  <tr> 
 @if($value->Evaluation_Status == 'No')
 <th><a href="{{route('user.show',['id'=>$value->pi_id])}}"><span style="color: blue;">{{$value->Name}}</span></a></th>
@elseif(($value->blacklist == 'Yes') && ($value->name == $value->Name))
 <th><a href="{{route('user.show',['id'=>$value->pi_id])}}"><span style="color: red;">{{$value->Name}}</span></a></th>
 @else 
<th><a href="{{route('user.show',['id'=>$value->pi_id])}}">{{$value->Name}}</a></th>
 @endif 
 <th> 
 {{$value->Evaluation_Status}} 
 </th> 

<th>{{ \Carbon\Carbon::parse($value->created_at)->format('d/m/Y')}}</th>

 <th><form action="{{ url('/home/'.$value->pi_id.'/delete') }}" method="get"> 
 {{ csrf_field() }} 
 <button type="submit">Delete</button> 
 </form></th> 
 </tr> 

 @endforeach

Controller.php这样

   $data = DB::table('personal_infos')
   ->select('personal_infos.id as pi_id','personal_infos.Name','verifications.name','verifications.blacklist','evaluations.Evaluation_Status', 'evaluations.created_at')
   ->join('verifications','verifications.id','=','verifications.id')
   ->join('evaluations', 'evaluations.user_id', '=', 'personal_infos.id')
   ->where('personal_infos.deleted_at', NULL)
   ->orderBy('personal_infos.created_at', 'desc')
   ->get(); 

    return view('home',compact('data'));

Answer 1

通过更改

解决了问题

->join('verifications','verifications.id','=','verifications‌.id')

到

->join('verifications','verifications.id','=','personal_infos.id')

Controller.php

中的

get（）函数获取多个相同的数据laravel

1 个答案: