Question

当我通过php文件通过电子邮件发送时，我无法正确显示我的html代码（没有html标签）。我收不到$header或$nmessage，以便在收件人收到电子邮件时正确显示？

我的php脚本如下所示，其中省略了html代码：

<?php

if(@$_REQUEST['weakPassword'] != "TEST")
{
echo "failed";
die();
}

function mail_attachment_from_file($the_file, $filename , $mailto, $from_mail, $from_name, $replyto, $subject, $message) 
{
$content = $the_file;
$content = chunk_split(base64_encode($content));
$uid = md5(uniqid(time()));
$header = "From: ".$from_name." <".$from_mail.">\r\n";
$header .= "Reply-To: ".$replyto."\r\n";
$header .= "MIME-Version: 1.0\r\n";
$header .= "Content-Type: multipart/mixed; boundary=\"".$uid."\"\r\n\r\n";
$nmessage = "--".$uid."\r\n";
$nmessage .= "Content-type:text/plain; charset=iso-8859-1\r\n";
$nmessage .= "Content-Transfer-Encoding: 7bit\r\n\r\n";
$nmessage .= $message."\r\n\r\n";
$nmessage .= "--".$uid."\r\n";
$nmessage .= "Content-Type: application/octet-stream; name=\"".$filename."\"\r\n";
$nmessage .= "Content-Transfer-Encoding: base64\r\n";
$nmessage .= "Content-Disposition: attachment; filename=\"".$filename."\"\r\n\r\n";
$nmessage .= $content."\r\n\r\n";
$nmessage .= "--".$uid."--";

mail($mailto, $subject, $nmessage, $header);

return true;
}

$to = @$_REQUEST['emailGuest'];
$from = @$_REQUEST['emailFrom'];

$subject = @$_REQUEST['emailSubject'];

$message = '
<html>
// HTML code
</html>';

$fileName = @$_REQUEST['fileName'];

$sep = sha1(date('r', time()));

// Read in our file attachment
$the_file = file_get_contents($_FILES['Filedata']['tmp_name']);

mail_attachment_from_file($the_file, $fileName , $to, $from, "BLAH", $from, $subject, $message);

echo "done";

?>

Answer 1

将您的Content-Type更改为：

$nmessage .= "Content-type: text/html\r\n";

由此：

$nmessage .= "Content-type:text/plain; charset=iso-8859-1\r\n";

检查https://linux.die.net/man/3/strtoul：

通过PHP文件通过电子邮件发送HTML

1 个答案: