Question

我有这样的路线

路线:: get（'/ {zoneSlug} / {categorySlug} / {sightSlug}'，...

示例：

{zoneSlug}有一个表格，如伦敦或巴黎

{categorySlug}有许多形式，如：

猫

或： cat / subcat

或： car / subcat / subcat3 /..

和{sightSlug}有一个表格，如eiffel

所以我喜欢这些地址：

 example.com/paris/category/effel
 ...
 example.com/paris/category/subcategory2/.../subcategory5/effel

我尝试在app\Providers\RouteServiceProvider.php

中绑定它

.
        Route::bind('zoneSlug' , function ($value) {return Zone::whereSlug($value)->firstOrFail();});


        Route::bind('categorySlug', function ($categorySlug, $route) {dd($route);
          $zone = $route->parameter('zoneSlug');
          return Category::whereSlug($categorySlug)->firstOrFail();
        });

        Route::bind('sightSlug', function ($sightSlug, $route) {dd($route);
          $zone = $route->parameter('zoneSlug');
          $category = $route->parameter('categorySlug');
          return Sight::whereZones_id($zone->id)->whereCategories_id($category->id)->whereSlug($sightSlug)->firstOrFail();
        });

绑定代码适用于：example.com/paris/category/effel ...但不适用于

example.com/paris/category/subcategory2/.../subcategoryn/effel

我该怎么做？

Answer 1

我建议超越你的URI结构。您的类别更好地位于查询字符串中 example.com/paris/eiffel?categories=category/subcategory,category/subcategor2或example.com/paris/eiffel?category=category/subcategory&category=category/subcategory2。

RouteServiceProvider嵌套类别绑定

1 个答案: