Question

我试图显示两条消息： 1.活动前一天 2.活动当天事件发生后的日期消息正常。我试图添加＆＃34;距离= 1＆＃34;这似乎是问题...

var countDownDate = new Date("<? echo $mounthname; ?> <? echo $d[2]; ?>, <? echo $d[0]; ?> <? echo $hourresp; ?>:00").getTime();
var x = setInterval(function() {
  var now = new Date().getTime();
  var distance = countDownDate - now;
  var days = Math.floor(distance / (1000 * 60 * 60 * 24));
  document.getElementById("countdown").innerHTML = " <? echo $line_within; ?> " + days + " <? echo $line_days; ?> ";
  if (distance === 1) {
    clearInterval(x);
    document.getElementById("countdown").innerHTML = "<? echo $line_eventistomorrow; ?>";
  }
  if (distance === 0) {
    clearInterval(x);
    document.getElementById("countdown").innerHTML = "<? echo $line_eventistoday; ?>";
  }
  if (distance < 0) {
    clearInterval(x);
    document.getElementById("countdown").innerHTML = "<? echo $line_eventisover; ?>";
  }
}, 400);

Answer 1

当您要检查distance时，您需要检查days。

（另请注意Math.floor会在这里给你一个一个错误;你想要Math.ceil。而且这种数学确实不会给你读数＆＃ 34;明天＆＃34;以及＆＃34;昨天＆＃34;而是你从现在开始24小时后＃34;以及＆＃34; 24小时前＆＃34;。用于真实的日期比较我建议像moment.js那样简化了大部分内容。）

＆＃13;

var countDownDate = new Date("December 1, 2017").getTime();
var now = new Date().getTime();
var distance = countDownDate - now;
console.log(distance); // this will not be 1 unless the countdown date is one millisecond in the future
var days = Math.ceil(distance / (1000 * 60 * 60 * 24));
console.log(days); // this is what you want
if (days === 1) {
  // ...
} // etc

＆＃13;

试图按距离计算计数器消息

1 个答案: