Question

我正在使用SAS，我有一个这样的数据框：

表1

+------+------------+-----------+
| name |    date    |    time   |
+------+------------+-----------+
| A    |  7-May-08  |  09:01:41 |
| A    |  7-May-08  |  09:01:41 |
| A    |  7-May-08  |  09:03:20 |
| A    |  7-May-08  |  09:04:41 |
| A    |  7-May-08  |  11:32:41 |
| A    |  8-May-08  |  09:06:00 |
| A    |  8-May-08  |  09:06:01 |
| A    |  8-May-08  |  12:32:41 |
| B    |  7-May-08  |  09:00:01 |
| B    |  7-May-08  |  09:00:01 |
| B    |  7-May-08  |  11:33:41 |
| B    |  9-May-08  |  09:05:59 |
| B    |  9-May-08  |  11:35:41 |
| B    |  9-May-08  |  11:36:41 |
| B    |  9-May-08  |  11:37:41 |
| B    |  12-May-08 |  11:27:41 |
| B    |  12-May-08 |  11:27:41 |
+------+------------+-----------+

现在我想做两个主要的操作：

1-如果每个名称和日期变量的时间值在9:00:01和9:05:59之间，则删除此间隔中的第一行;

2-对于上一步，如果下一行的时间值与第一行相同，则在此时间间隔内删除所有行。

例如，table1最后应该是这样的：

+------+-----------+----------+
| name |   date    |   time   |
+------+-----------+----------+
| A    | 7-May-08  | 09:03:20 |
| A    | 7-May-08  | 9:04:41  |
| A    | 7-May-08  | 11:32:41 |
| A    | 8-May-08  | 9:06:00  |
| A    | 8-May-08  | 9:06:01  |
| A    | 8-May-08  | 12:32:41 |
| B    | 7-May-08  | 11:33:41 |
| B    | 9-May-08  | 11:35:41 |
| B    | 9-May-08  | 11:36:41 |
| B    | 9-May-08  | 11:37:41 |
| B    | 12-May-08 | 11:27:41 |
| B    | 12-May-08 | 11:27:41 |
+------+-----------+----------+

我该怎么做？

Answer 1

我假设数据按time为每组name + date排序，目的是＆＃34;如果下一行的时间值与第一行＆＃34;。

然后，查询非常简单：

data have;
input @1 name $1 @3 date date11. @13 time time.;
format date date11.;
format time time.;
datalines;
A 7-May-08  09:01:41
A 7-May-08  09:01:41
A 7-May-08  09:03:20
A 7-May-08  09:04:41
A 7-May-08  11:32:41
A 8-May-08  09:06:00
A 8-May-08  09:06:01
A 8-May-08  12:32:41
B 7-May-08  09:00:01
B 7-May-08  09:00:01
B 7-May-08  11:33:41
B 9-May-08  09:05:59
B 9-May-08  11:35:41
B 9-May-08  11:36:41
B 9-May-08  11:37:41
B 12-May-08 11:27:41
B 12-May-08 11:27:41
;
run;

proc sql;
create table want as select *
from have
group by name, date
having min(time) not between '09:00:01't and '09:05:59't
    or time ne min(time)
;quit;

如何使用SAS删除特定时间间隔内的第一行或第一组行？

1 个答案: