Question

我在广告客户，advertiser_clicks和advertiser_cost中有三个表格，其中我使用了多个聚合函数的连接。但是我无法从表格中获取实际记录。请在下面的表格结构中找到。

表1：广告客户

................
id      name
................
1     Your Survey
2     Vindale

表2：advertiser_clicks 在此表中，adv_id是广告客户表 id

的外键

.............................................................
id    adv_id    survey_id   survey_name  clicks  dt_datetime
.............................................................
1       1        101        survey1       1       2017-11-30
2       2        102        survey2       1       2017-11-29
3       1        103        survey3       1       2017-11-28

表3：advertiser_cost 在此表中，a_click_id是advertiser_clicks表的外键 adv_id

.......................................................
ac_id   a_click_id   cpi    conversion  cost   profit  
......................................................
  1       1          10       1           8      2
  2       2          10       1           5      5
  3       3          5        1           5      5

我想要下面的输出： - 当我选择开始日期：2017-11-29并结束：2017-11-30在哪里条件然后我想要低于输出。这里总点击，cpi，成本和利润是该日期范围之间所有数据的总和。

.............................................................
adv_id    advertiser     totalclick    cpi    cost   profit
.............................................................
   1       Your survey       2          20     13     8
   2        vindale          0           0     0      0

我写了下面的查询，它返回了确切的数据在那个日期范围之间，但我不会返回vindale的记录广告客户为零值。请找到我的以下查询。

SELECT sum(advertiser_clicks.`clicks`) as totalclick,sum(advertiser_cost.cpi) as revenue,sum(advertiser_cost.`conversion`) as conversion,sum(advertiser_cost.`cost`) as cost,SUM(advertiser_cost.profit) as profit,advertiser.name as advertiser,advertiser.id as adv_id FROM `advertiser_clicks` LEFT JOIN advertiser_cost on advertiser_cost.a_click_id=advertiser_clicks.`id` inner join advertiser on advertiser.id=advertiser_clicks.`adv_id` where advertiser_clicks.`dt_datetime`>='2017-11-29' and advertiser_clicks.`dt_datetime`<='2017-11-30' group by advertiser.name,advertiser.id

我的查询返回此输出： -

.............................................................
adv_id    advertiser     totalclick    cpi    cost   profit
.............................................................
   1       Your survey       2          20     13     8

Answer 1

您好我已经解决了我的问题： -

SELECT sum(advertiser_clicks.`clicks`) as totalclick,sum(advertiser_cost.cpi) as revenue,sum(advertiser_cost.`conversion`) as conversion,sum(advertiser_cost.`cost`) as cost,SUM(advertiser_cost.profit) as profit,advertiser.name as advertiser,advertiser.id as adv_id FROM `advertiser` left join advertiser_clicks on advertiser.id=advertiser_clicks.`adv_id` and (advertiser_clicks.`dt_datetime` between '$startdate' and '$enddate' ) LEFT JOIN advertiser_cost on advertiser_cost.a_click_id=advertiser_clicks.`id` group by advertiser.name,advertiser.id

如何使用group by的多个聚合函数

1 个答案: