我的字符串文字是赞 -
1) .....bla ..bla...
2)...bla.. bla…bla.
3).bla.. bla…bla.
点不是静态的。我想仅从开始时删除点。不是所有点
我试过这个
NSString *newString = [myString stringByReplacingOccurrencesOfString:@"." withString:@""];
但这是删除所有点。
答案 0 :(得分:3)
试试这个。
NSString* regex = @"^\\.*";
NSString* input = @"....abc..z";
NSString* output = [input stringByReplacingOccurrencesOfString:regex withString:@"" options:NSRegularExpressionSearch range: [input rangeOfString:input]];
答案 1 :(得分:1)
var test = "...abc";
while test.hasPrefix(".") {
test.remove(at: test.startIndex)
}
//test variable will have dots removed at the start.
试试这个。
答案 2 :(得分:0)
试试这个:
NSString *str = @"...Videt...IDL";
__block NSInteger loc = 0;
[str enumerateSubstringsInRange:NSMakeRange(0, str.length) options:NSStringEnumerationByWords usingBlock:^(NSString * _Nullable substring, NSRange substringRange, NSRange enclosingRange, BOOL * _Nonnull stop) {
loc = substringRange.location;
*stop = YES;
}];
NSString *convStr = [str substringFromIndex:loc];
NSLog(@"%@", convStr);
答案 3 :(得分:0)
NSString *str = @"....bla .... bla..... bla";
NSCharacterSet *charSet = [NSCharacterSet letterCharacterSet];
int letterNO = 0;
for (int i =0; i<str.length; i++)
{
NSString *letter = [NSString stringWithFormat:@"%c",[str characterAtIndex:i]];
if ([letter rangeOfCharacterFromSet:charSet].location != NSNotFound)
{
letterNO = i;
break;
}
}
NSString * newString = [str substringFromIndex:letterNO];
NSLog(@"newString %@",newString);