Question

我正在Laravel 5.4上构建一个小型应用程序，我正在从这种关系中获取数据集：

$meetings = Company::where('name', 'Atlanta Ltd')
    ->withCount(['interactions as investors'=> function ($q) {
        $q
            ->whereBetween('schedule', [Carbon::now()->subMonths(6), Carbon::now()->subMonths(1)])
            ->whereHas('contactsAssociation', function ($q) {
                $q->whereHas('company', function ($q) {
                    $q->where('type', 'like', 'Investor');
                });
            });
    }])->get()
    ->transform(function ($company) {
        $company->investors_count = $company->interactions
            ->pluck('investors_count')
            ->sum();
        return $company;
    });

目前我在该特定日期之间获得了投资数量的交互次数，我想获取某些日期字段之间的计数，即假设我想要连续6个月获取数据，我的意思是6个不同月份的数据是这样的：

->whereBetween('schedule', [Carbon::now()->subMonths(6), Carbon::now()->subMonths(5)])

和

->whereBetween('schedule', [Carbon::now()->subMonths(5), Carbon::now()->subMonths(4)])

和

->whereBetween('schedule', [Carbon::now()->subMonths(4), Carbon::now()->subMonths(3)])

该列表与上述差异类似。而且我不想实现多个foreach循环，有Laravel Collection的任何出路我可以操纵这些数据得到输出。请指导我。感谢。

修改让我以更好的方式解释，目前我正在使用此代码来获取我想要的数据：

public function investorGraphData(Request $request)
{
    $weekInvestorData = $weekResearchData = [];

    if($request->timeFormat == 'month')
    {
        for($i=0; $i<6; $i++)
        {
            $meetings = Company::where('name', $request->client)
                ->withCount(['interactions as investors'=> function ($q) use($i) {
                    $q
                        ->whereBetween('schedule', [Carbon::now()->subMonth($i+1), Carbon::now()->subMonth($i)])
                        ->whereHas('contactsAssociation', function ($q) {
                            $q->whereHas('company', function ($q) {
                                $q->where('type', 'like', 'Investor');
                            });
                        });
                }])
                ->withCount(['interactions as research' => function($q) use($i) {
                    $q
                        ->whereBetween('schedule', [Carbon::now()->subMonth($i+1), Carbon::now()->subMonth($i)])
                        ->whereHas('contactsAssociation', function ($q) {
                            $q->whereHas('company', function ($q) {
                                $q->where('type', 'like', 'Research');
                            });
                        });
                }])
                ->get();
            $weekInvestorData[] = $meetings[0]->investors_count;
            $weekResearchData[] = $meetings[0]->research_count;
        }

        return response()->json(['investor' => $weekInvestorData, 'research' => $weekResearchData], 200);
    }
    elseif ($request->timeFormat == 'week')
    {
        for($i=0; $i<6; $i++)
        {
            $meetings = Company::where('name', $request->client)
                ->withCount(['interactions as investors'=> function ($q) use($i) {
                    $q
                        ->whereBetween('schedule', [Carbon::now()->subWeek($i+1), Carbon::now()->subWeek($i)])
                        ->whereHas('contactsAssociation', function ($q) {
                            $q->whereHas('company', function ($q) {
                                $q->where('type', 'like', 'Investor');
                            });
                        });
                }])
                ->withCount(['interactions as research' => function($q) use($i) {
                    $q
                        ->whereBetween('schedule', [Carbon::now()->subWeek($i+1), Carbon::now()->subWeek($i)])
                        ->whereHas('contactsAssociation', function ($q) {
                            $q->whereHas('company', function ($q) {
                                $q->where('type', 'like', 'Research');
                            });
                        });
                }])
                ->get();
            $weekInvestorData[] = $meetings[0]->investors_count;
            $weekResearchData[] = $meetings[0]->research_count;
        }
        return response()->json(['investor' => $weekInvestorData, 'research' => $weekResearchData], 200);
    }
    else
        return response()->json(['message' => 'No input given'], 200);
}

有没有办法通过收集来缩短这段代码？

Answer 1

您可以尝试将列命名为不同的名称，

例如：

$meetings = Company::where('name', 'Atlanta Ltd')
    ->withCount(['interactions as investors'=> function ($q) {
        $q
            ->whereBetween('schedule as schedule6to5', [Carbon::now()->subMonths(6), Carbon::now()->subMonths(5)])
            ->whereBetween('schedule as schedule5to4', [Carbon::now()->subMonths(5), Carbon::now()->subMonths(4)])
            ->whereBetween('schedule as schedule4to3', [Carbon::now()->subMonths(4), Carbon::now()->subMonths(3)])
            ->whereHas('contactsAssociation', function ($q) {
                $q->whereHas('company', function ($q) {
                    $q->where('type', 'like', 'Investor');
                });
            });
    }])->get()
    ->transform(function ($company) {
        $company->investors_count = $company->interactions
            ->pluck('investors_count')
            ->sum();
        return $company;
    });

可能会有效。

如何在Laravel中获取多个whereBetween记录

1 个答案: