Question

我想在依赖于json数据ID的两个不同json数组上合并相同的特定json对象。

JSON数据集1

{
    "Product":[
                {
                "product_id": "123",
                "location_id": "222",
                "product_code": "abc",
                },
                {
                "product_id": "456",
                "location_id": "111",
                "product_code": "xyz",
                }
            ]
}

JSON数据集2

{
    "Location":[

            {
                "location_id": 111,
                "location_name": "alpha"
            },
            {
                "location_id": 222,
                "location_name": "tango"
            }


        ]
}

结果将是这样的

{
    "Product":[

                {
                    "product_id": "456",
                    "location_id": "111",
                    "product_code": "xyz",
                    "location_name": "alpha"
                },
                {
                    "product_id": "123",
                    "location_id": "222",
                    "product_code": "abc",
                    "location_name": "tango"
                }
            ]
}

到目前为止，这是我已经完成的代码。

var finalJson = {};

                    _.each(_.keys(productArray,locationArray), function(key) {
                        finalJson[key] = _.flatten(_.zip(productArray[key], locationArray[key]));
                    });

                    console.log(finalJson);

Answer 1

一个简单的算法可能是使用嵌套循环来遍历两个数组，如下所示：

let allProducts = [{
    "product_id": "123",
    "location_id": "222",
    "product_code": "abc",
  },
  {
    "product_id": "456",
    "location_id": "111",
    "product_code": "xyz",
  }
];


let allLocations = [

  {
    "location_id": 111,
    "location_name": "alpha"
  },
  {
    "location_id": 222,
    "location_name": "tango"
  }
];

let result = allProducts.map((product) => {
  let matchingLocation = allLocations.find((location) => {
    return location.location_id == product.location_id;
  });
  return Object.assign(product, matchingLocation);
})

console.log(result);

Answer 2

使用location id作为键来创建位置的散列图，然后迭代Product数组

＆＃13;

let arr1 = {
  "Product": [{
    "product_id": "123",
    "location_id": "222",
    "product_code": "abc",
  }, {
    "product_id": "456",
    "location_id": "111",
    "product_code": "xyz",
  }]
}

let arr2 = {
  "Location": [
    {
      "location_id": 111,
      "location_name": "alpha"
    }, {
      "location_id": 222,
      "location_name": "tango"
    }
  ]
}
let locIds= _.keyBy(arr2.Location, 'location_id');
_.each(arr1.Product, (o) => _.assign(o, locIds[o.location_id]));

console.log(arr1.Product)

＆＃13;

.as-console-wrapper{max-height:100%!important}

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

＆＃13;

合并两个不同json数组中的相同特定json对象

2 个答案: