在python中获取名称错误消息

时间:2017-11-29 18:44:19

标签: python scipy anaconda

我在anaconda进口了scipy,我打电话给:

messy_list = ["a", 2, 3, 1, False, [1, 2, 3]] for val in list(messy_list): if type(val) != int: messy_list.remove(val) print(messy_list) # [2, 3, 1]

并致电:

from scipy import misc

从您的桌面调用图像,但我收到错误消息:

data = misc.imread(/Users/Desktop...)

1 个答案:

答案 0 :(得分:-1)

尝试:

function mySum(A1NotationString){
  var sum=0;
  SpreadsheetApp.getActiveSheet().getRange(A1NotationString).getValues().forEach(function(item){sum+=Number(item);});
  return sum;
}


function myAvg(A1NotationString){
  var sum=0;
  var n=0;
  SpreadsheetApp.getActiveSheet().getRange(A1NotationString).getValues().forEach(function(item,i){sum+=Number(item);if(Number(item)>0){n=i+1;}});
  return sum/n;
}

或者

from scipy import misc
assert misc

或者:

from scipy import misc
print(dir(misc))