我在下面有这个脚本:
---------Part 1--------
SELECT
COLUMN_NAME
FROM
(SELECT
SC.name as TABLE_SCHEMA,
t.name as TABLE_NAME,
ind.name as indexName,
ind.type_desc AS type_Index,
SUBSTRING((SELECT ', ' + AC.name
FROM DATA.sys.[tables] AS T
INNER JOIN DATA.sys.[indexes] I ON T.[object_id] = I.[object_id]
INNER JOIN DATA.sys.[index_columns] IC ON I.[object_id] = IC.[object_id] AND I.[index_id] = IC.[index_id]
INNER JOIN DATA.sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id]
WHERE Ind.[object_id] = I.[object_id] AND Ind.index_id = I.index_id AND IC.is_included_column = 0
ORDER BY IC.key_ordinal
FOR XML PATH('')), 2, 8000) AS COLUMN_NAME
FROM DATA.sys.indexes ind
INNER JOIN DATA.sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id
INNER JOIN DATA.sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN DATA.sys.tables t ON ind.object_id = t.object_id
INNER JOIN DATA.sys.schemas SC ON t.schema_id = SC.schema_id
WHERE SC.name ='SCHEMA1') AS SubQ
WHERE
COLUMN_NAME IN
-------Part 2-------
(SELECT COLUMN_NAME
FROM DATA.INFORMATION_SCHEMA.COLUMNS
WHERE DATA_TYPE IN ('nchar', 'nvarchar')
AND TABLE_SCHEMA IN ('SCHEMA1', 'SCHEMA2'))
当我运行第1部分或第2部分时,我得到了最好的列,并且两个结果是相同的,但是当我运行所有脚本时,它不会显示任何内容,也没有错误。
请帮忙吗? 谢谢