如何在pygame中使用用户的任何输入从一个屏幕移动到另一个屏幕？

Question

def ScytaleCipher():
    Title = cipherFont.render("Scytale Cipher", 10, textColour)
    Plaintext = inputFont.render("Plaintext: ", 10, textColour)
    Shift = inputFont.render("Shift: ", 10, textColour)
    background = pg.Surface(screen.get_size())
    background.fill(screenGray)
    background.blit(Title, (115,10))
    background.blit(Plaintext, (10,500))
    background.blit(Shift, (10,555))

    PlaintextBox = InputBox(125,500)
    ShiftBox = InputBox(75,555)

    EncryptButton = Button('Encrypt',340,490,125,50,buttonGray2)
    DecryptButton = Button('Decrypt',340,545,125,50,buttonGray2)
    BackButton = Button('Back', 10,10,100,50,buttonGray2)
    buttonsGroup = pg.sprite.Group(BackButton,EncryptButton,DecryptButton)

    Encrypt = False
    Decrypt = False

    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                pg.quit()
                sys.exit()
            elif BackButton.isPressed(event):
                Menu()
            elif EncryptButton.isPressed(event):
                Encrypt = True
            elif DecryptButton.isPressed(event):
                Decrypt = True

            PlaintextBox.handleEvent(event)
            ShiftBox.handleEvent(event)

        screen.blit(background,(0, 0))

        buttonsGroup.draw(screen)
        PlaintextBox.drawBox(screen)
        ShiftBox.drawBox(screen)

        if Encrypt == True:
            cipher = ScytaleEncryption(PlaintextBox.text,ShiftBox.text)
            label1 = inputFont.render(cipher,1,textColour)
            screen.blit(label1,(500,550))
            for event in pg.event.get():
                if event.type == pg.KEYDOWN:
                    if event.key == pg.K_LEFT or event.key == pg.K_RIGHT:
                        Menu()
                    elif event.type == pg.MOUSEBUTTONDOWN:
                        Menu()

        pg.display.flip()
        clock.tick(60)

上面的代码是一个从菜单中调用的函数，它运行一个密码。密码运行后，我想要用户做的下一件事就是把它们带回那个菜单。

我试过，但我认为这可能是因为if语句中的第二轮for event in events

我们非常感谢您能想到的任何其他改进

提前致谢！