Question

所以我有一长串的自行车手，我需要将它排成一个结构数组，所以它就是

种族，名字，姓氏，年龄，团队，国籍，安置和运行时间。

到目前为止，我已设法做到这一点，但当我来到一个有两个名字的人（在这个问题Mads Wurst）时，它会混乱我的整个阵列，无论我尝试它似乎都没有解决它。

名称列表如下所示：

ParisRoubaix“Mickael DELAGE”32 FDJ FRA 43 5:50:48

ParisRoubaix“Iljo KEISSE”35 QST BEL 44 5:50:48

ParisRoubaix“Matthieu LADAGNOUS”33 FDJ FRA 45 5:50:48

ParisRoubaix“Mads Wurtz SCHMIDT”23 KAT DEN 46 5:50:48

ParisRoubaix“Dylan GROENEWEGEN”24 TLJ NED 47 5:50:48

ParisRoubaix“Reto HOLLENSTEIN”32 KAT SUI 48 5:50:48

我的代码看起来像这样：

int printAllRiders(void){
  char full_data_array[RACE_DATA_SIZE];

  race_results *each_race = malloc(sizeof(race_results)*RACE_DATA_SIZE);

  FILE *inputp;
  inputp = fopen("cykelloeb-2017.txt", "r");

  int i = 0;

  if(inputp != NULL)
  {
   while(i<50/*(temp_var = fgetc(inputp)) !=EOF*/)
   {
  fscanf(inputp, " %s \"%[-A-z] %[ ABCDEFGHIJKLMNOPQRSTUVWXYZ'  ]\" %[0-9] %[A-Z] %[A-Z] %s %s", 
    each_race[i].race, 
    each_race[i].name_first, 
    each_race[i].name_last, 
    each_race[i].age, 
    each_race[i].team, 
    each_race[i].nationality, 
    each_race[i].placement, 
    each_race[i].finishing_time);

  printf("Race: %s\n, first name: %s\n, last name: %s\n, age: %s\n, team: %s\n, nationality: %s\n, placement: %s\n, time: %s\n", 
    each_race[i].race, 
    each_race[i].name_first, 
    each_race[i].name_last, 
    each_race[i].age, 
    each_race[i].team, 
    each_race[i].nationality, 
    each_race[i].placement, 
    each_race[i].finishing_time);
  i++;
}
 } else {
printf("ERROR: Input file could not be opened");
exit(EXIT_FAILURE);
 }

fclose(inputp);
full_data_array[i] = '\0';
  }

对结构数组中的名称进行排序

0 个答案: