Question

说实话，我有以下定义：

DECLARE @referenceDate DATETIME
SET @referenceDate = '20171123';
DECLARE @intervalDays INT
SET @intervalDays = 30
DECLARE @weekMonday DATETIME
SET @weekMonday = '20171204';
DECLARE @weekSunday DATETIME
SET @weekSunday = '20171210';

恰好在这些日期发生了重要的事情：

@referenceDate
DATEADD(day, 1 * @intervalDays, @referenceDate);
DATEADD(day, 2 * @intervalDays, @referenceDate);
DATEADD(day, 3 * @intervalDays, @referenceDate);

等等。

我想知道这件事是否重要＆＃39;将（也）发生在@weekMonday和@weekSunday之间的指定周内。

我已获得SQL Server版本11.0.6251.0标准版，德语本地化。谢谢你的帮助。

Answer 1

我用模数找到了这个解决方案：

IF (DATEDIFF(day, @referenceDate, @weekMonday) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 1, @weekMonday)) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 2, @weekMonday)) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 3, @weekMonday)) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 4, @weekMonday)) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 5, @weekMonday)) % @intervalDays = 0 OR
    DATEDIFF(day, @referenceDate, DATEADD(day, 6, @weekMonday)) % @intervalDays = 0)
   SELECT @monday AS found

也许有人知道如何进一步简化它？感谢。

Answer 2

我不清楚你在找什么。

如果在范围内：

DECLARE @referenceDate DATETIME
SET @referenceDate = '20171123';
DECLARE @intervalDays INT
SET @intervalDays = 30
DECLARE @weekMonday DATETIME
SET @weekMonday = '20171204';
DECLARE @weekSunday DATETIME
SET @weekSunday = '20171210';

SELECT
    CASE 
        WHEN DATEADD(day, @intervalDays, @referenceDate) BETWEEN @weekMonday AND @weekSunday 
            THEN @intervalDays
        WHEN DATEADD(day, @intervalDays + 30, @referenceDate) BETWEEN @weekMonday AND @weekSunday 
            THEN @intervalDays + 30 
        ELSE 0 
    END AS [IsReferenceDatePlusIntervalDaysWithinTheDateRange]

到目前为止的天数：

SELECT DATEDIFF(day, @referenceDate, @weekMonday) AS [NumberOfDaysBetweenReferenceDateToWeekMonday]

找出添加了天数间隔的日期是否在一周内

2 个答案: