我正在OSX中构建一个.net核心2.0应用程序,它是一个WebAPI应用程序,当命中API端点时会创建带有虚拟数据的.xlsx。当我尝试运行它(dotnet run)时,我得到了
System.UnauthorizedAccessException: Access to the path '/Users/myuser/projects/myproject' is denied. ---> System.IO.IOException: Permission denied
我已经尝试将其作为sudo运行并更改它正在写入的文件夹而且没有帮助
// GET api/values/5
[HttpGet("{id}")]
public string Get(int id)
{
CreatePackage("./");
return "value";
}
public void CreatePackage(string filePath)
{
using (SpreadsheetDocument package = SpreadsheetDocument.Create(filePath, SpreadsheetDocumentType.Workbook))
{
CreateParts(package);
}
}
private void CreateParts(SpreadsheetDocument document)
{
WorkbookPart workbookPart = document.AddWorkbookPart();
GenerateWorkbookPartContent(workbookPart);
WorksheetPart worksheetPart = workbookPart.AddNewPart<WorksheetPart>("rId1");
GenerateWorksheetPartContent(worksheetPart);
}
private void GenerateWorkbookPartContent(WorkbookPart workbookPart)
{
Workbook workbook = new Workbook();
workbook.AddNamespaceDeclaration("r", "http://schemas.openxmlformats.org/officeDocument/2006/relationships");
Sheets sheets = new Sheets();
Sheet sheet = new Sheet() { Name = "Sheet", SheetId = (UInt32Value)1U, Id = "rId1" };
sheets.Append(sheet);
workbook.Append(sheets);
workbookPart.Workbook = workbook;
}
private void GenerateWorksheetPartContent(WorksheetPart worksheetPart)
{
Worksheet worksheet = new Worksheet();
SheetData sheetData = new SheetData();
Row row = new Row();
Cell cell = new Cell() { CellReference = "A1", DataType = CellValues.InlineString };
InlineString inlineString = new InlineString();
Text text = new Text();
text.Text = "hello";
inlineString.Append(text);
cell.Append(inlineString);
row.Append(cell);
sheetData.Append(row);
worksheet.Append(sheetData);
worksheetPart.Worksheet = worksheet;
}
这是该类的主要部分,我正在项目文件夹中创建文件(现在)。我看到有关为CLI的所有文件提供读写权限的帖子,但这看起来并不理想。另外我看到this关于在文件上设置属性,但这是OpenXml电子表格创建方法,据我所知,它没有关于设置文件权限的任何内容(并且无论如何它都需要在文件夹中)< / p>
非常感谢任何帮助
答案 0 :(得分:3)
我弄清楚了,我发送的文件路径是文件路径而不是文件路径,问题已解决
[HttpGet("{id}")]
public string Get(int id)
{
CreatePackage("./testfile.xlsx");
return "value";
}