我有一个标签式活动1到5.如果我从3移动到5然后在后退按下我想从5切换回3,即在背面按下我想要移回上一个标签。请帮忙
答案 0 :(得分:1)
使用以下代码实现它。(代码也经过测试。)
1.Initialise一个整数列表和一个布尔值;
private boolean isBackPressed = false;
private boolean isBackPressedOnce = false;
private List<Integer> tabsInBack = new ArrayList<>();
2.现在你的onTabSelectedListener必须像
tabs.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
if(!isBackPressed){
tabsInBack.add(tab.getPosition());}
else {
isBackPressed = false;}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
3(i)。现在你的onBackPressed()函数必须是,(一个标签然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
3(ii)。现在你的onBackPressed()函数必须是,(返回所有选中的标签,然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
if(isBackPressedOnce )
{
super.onBackPressed();
}
else
{
isBackPressedOnce = true;
}
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
让我知道它是否有帮助。
答案 1 :(得分:0)
这对我有用:) 它的工作原理完全类似于whatsapp
@Override public void onBackPressed(){
//If first tab is open, then quit
if (viewPager.getCurrentItem() == 0) {
super.onBackPressed();
}else {
//If any other tab is open, then switch to first tab
viewPager.setCurrentItem(0);
}
}