我试图断言元素的存在,我可以使它工作,但现在按照我想要的方式。
我有一个常见的函数文件: -
from selenium.common.exceptions import NoSuchElementException
def is_element_present_common(self, how, what):
try:
self.driver.find_element(by=how, value=what)
except NoSuchElementException as e:
return False
return True
...和我的主文件: -
import unittest
from Common import common_functions, initialisation, login
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as ec
from selenium.common.exceptions import NoSuchElementException
class QuickTestPlanLogin(unittest.TestCase):
def setUp(self):
self.driver = initialisation.start_webdriver()
self.driver = initialisation.start_sap(self.driver)
def tearDown(self):
self.driver.close()
def is_element_present(self, how, what):
try:
self.driver.find_element(by=how, value=what)
except NoSuchElementException as e:
return False
return True
def test_login(self):
wait = initialisation.wait_for(self.driver)
self.driver = login.default_login(self.driver, "username", "password")
# self.assertTrue(self.is_element_present(By.ID, "my-projects-table_info"))
# self.assertTrue(common_functions.is_element_present_common(By.ID, "my-projects-table_info"))
有两个断言陈述。如果我运行第一个它工作正常,但它调用我不想要的is_element_present函数。我想从common_functions文件中调用is_element_present_common函数。每次运行第二个断言语句时,我都会收到以下错误: -
TypeError: is_element_present() missing 1 required positional argument: 'what'
我知道我错过了很简单的事情......
答案 0 :(得分:0)
将功能定义更改为:
def is_element_present_common(how, what):
和
将呼叫更改为is_element_present_common
功能:
self.assertTrue(common_functions.is_element_present_common(By.ID, "my-projects-table_info"))