我有两个maven项目，我想用一个作为对另一个的依赖。现在，我使用<?php
$servername = "localhost";
$username = "root";
$password = "";
$db = "item";
$conn = new mysqli($servername, $username, $password, $db);
$jsondata = file_get_contents( $_FILES['file']['tmp_name']);
$data = json_decode($jsondata, true);
$gstin = $data['gstin'];
$fp = $data['fp'];
$stmt = "INSERT INTO gstin (gstin, fp) VALUES('$gstin', '$fp')";
mysqli_query($conn, $stmt);
foreach ($data['b2b'] as $row1) {
$ctin = $row1['ctin'];
$cfs = $row1['cfs'];
$stmt = "INSERT INTO b2b (ctin, cfs) VALUES('$ctin', '$cfs')";
mysqli_query($conn, $stmt);
foreach($row1['inv'] as $row3){
$val = $row3['val'];
$inv_typ = $row3['inv_typ'];
$flag = $row3['flag'];
$updby = $row3['updby'];
$pos = $row3['pos'];
$idt = $row3['idt'];
$rchrg = $row3['rchrg'];
$cflag = $row3['cflag'];
$inum = $row3['inum'];
$chksum = $row3['chksum'];
$stmt = "INSERT INTO inv (val, inv_typ, flag, updby, pos, idt, rchrg, cflag,
inum, chksum) VALUES('$val', '$inv_typ', '$flag', '$updby', '$pos', '$idt',
'$rchrg', '$cflag', '$inum', '$chksum')";
$result = mysqli_query($conn, $stmt);
foreach($row3['inv'][0]['itms'] as $row2){
(isset($row2['itc']['tx_cs'])) ? $tx_cs=$row2['itc']['tx_cs'] : null;
$elg = $row2['itc']['elg'];
(isset($row2['itc']['tx_i'])) ? $tx_i = $row2['itc']['tx_i'] : null;
(isset($row2['itc']['tx_c'])) ? $tx_c =$row2['itc']['tx_c'] : null;
(isset($row2['itc']['tx_s'])) ? $tx_s = $row2['itc']['tx_s'] : null;
(isset($row2['itm_det']['samt'])) ? $samt = $row2['itm_det']['samt'] :
null;
(isset($row2['itm_det']['csamt'])) ? $csamt = $row2['itm_det']['csamt'] :
null;
(isset($row2['itm_det']['iamt'])) ? $iamt = $row2['itm_det']['iamt'] :
null;
(isset($row2['itm_det']['camt'])) ? $camt = $row2['itm_det']['camt'] :
null;
$rt = $row2['itm_det']['rt'];
$txval = $row2['itm_det']['txval'];
$stmt = "INSERT INTO itms (tx_cs, elg, tx_i, tx_c, tx_s, samt, csamt, rt,
txval, camt, iamt) VALUES('$tx_cs', '$elg', '$tx_i', '$tx_c', '$tx_s',
'$samt', '$csamt', '$rt', '$txval', '$camt', '$iamt')";
$result = mysqli_query($conn, $stmt);
}
}
}
构建了project1，并将其添加到project2，如下所示：
mvn clean install我可以在project2外部库文件夹中看到这个jar及其所有类。让我们说这个项目有<dependency>
<groupId>com.foo</groupId>
<artifactId>project1</artifactId>
<version>0.0.1-SNAPSHOT</version>
</dependency>
课程。当我尝试键入此类的名称时，IntelliJ会在上下文菜单中显示它，以便它知道它的存在。但是，只要我尝试实例化MyClass IntelliJ就说com.foo.MyClass。我是Spring的新手，所以我不确定这是否是我的代码或某种IntelliJ错误的问题。