Java重绘gridlayout

Question

我正在尝试重新绘制我在新游戏动作中创建的蛇游戏。它正在工作但它不能清除旧的蛇体或阻挡屏幕。

public class View extends JFrame implements ActionListener {

private static final long serialVersionUID = -2542001418764869760L;
public static int viewWidth = 20;
public static int viewHeight = 20;
private SidePanel side;

private JMenuBar menuBar;
private JMenuItem newGameButton;
private JMenu menu, mode;
private SnakeController sController;

private GamePanel gamePanel;

/*
 * Initialize the game's panels and add them to the window.
 */
public View() {

    menuBar = new JMenuBar();
    menu = new JMenu("Menu");
    menuBar.add(menu);

    newGameButton = new JMenuItem("New Game");
    menu.add(newGameButton);
    newGameButton.addActionListener(this);

    mode = new JMenu("Mode");
    menuBar.add(mode);

    this.setJMenuBar(menuBar);
    this.gamePanel = new GamePanel(this);

    this.side = new SidePanel(this);

    this.add(gamePanel, BorderLayout.CENTER);
    this.add(side, BorderLayout.EAST);

    Tuple position = new Tuple(10, 10);
    sController = new SnakeController(position, side, gamePanel);
    this.addKeyListener((KeyListener) new Listener());
    // this.requestFocus();

    pack();

}

public static void main(String args[]) {
    View window = new View();
    window.setTitle("og-snake");
    window.setSize(700, 400);
    window.setVisible(true);
    window.setResizable(false);
    window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

}

@Override
public void actionPerformed(ActionEvent e) {
    if (e.getSource() == newGameButton) {
        System.out.println("clicked");

        gamePanel.removeAll();
        gamePanel.revalidate();
        gamePanel.repaint();

        Tuple position = new Tuple(10, 10);

        sController = new SnakeController(position, side, gamePanel);
        sController.start();


    }

}

这是我的主要课程，它基本上使视图添加了侧面板和棋盘面板。所执行的动作是在游戏面板上的新游戏动作上完成的。

public class GamePanel extends JPanel {

public static ArrayList<ArrayList<ColorCell>> snakeGrid;
public static int viewWidth = 20;
public static int viewHeight = 20;
ArrayList<ColorCell> data; 
SnakeController sc ;
private View game;

public GamePanel(View game) {
    this.game = game;
    this.snakeGrid = new ArrayList<ArrayList<ColorCell>>();
    this.data = new ArrayList<ColorCell>();
    for (int i = 0; i < viewWidth; i++) {
        data = new ArrayList<ColorCell>();
        for (int j = 0; j < viewHeight; j++) {
            ColorCell c = new ColorCell(2);
            data.add(c);
        }
        snakeGrid.add(data);
    }
    setLayout(new GridLayout(viewWidth, viewHeight, 0, 0));
    setPreferredSize(new Dimension(400,400)); 

}

public void paintComponent(Graphics g) {
    super.paintComponent(g);
    for (int i = 0; i < viewWidth; i++) {
        for (int j = 0; j < viewHeight; j++) {
            add(snakeGrid.get(i).get(j).viewCell);
        }
    }
}

}

Answer 1

    gamePanel.removeAll();
    gamePanel.fillGrid();
    gamePanel.revalidate();
    gamePanel.repaint();
    Tuple position = new Tuple(10, 10);
    this.gamePanel = new GamePanel(this);
    this.add(gamePanel,BorderLayout.CENTER);

该代码并没有真正做任何事情。将组件添加到BorderLayout的CENTER时，它不会替换原始组件。

Swing绘画的工作方式是首先绘制添加的最后一个组件。所以这意味着新添加的面板被绘制，然后原始面板被涂在新添加的面板的顶部。

因此，由于您有逻辑从原始gamePanel中删除所有组件，因此无需创建新的gamePanel。只需重置游戏面板的状态即可。