如何为以下内容创建更简单的javascript函数：

Question

必须有一个可以使用的功能，它将极大地简化所有这些非常相似的替换。希望能够制作一个能够处理今年秋季所有收缩的功能，包括我，可能等等。

    // for can't
    s = s.replace(/cant/g, "ca{n't|n{| }not}");
    s = s.replace(/can't/g, "ca{n't|n{| }not}");
    s = s.replace(/Cant/g, "Ca{n't|n{| }not}");
    s = s.replace(/Can't/g, "Ca{n't|n{| }not}");

    //for can not
    s = s.replace(/can not/g, "ca{n't|{| }not}");
    s = s.replace(/Can not/g, "Ca{n't|{| }not}");


    // for won't
    s = s.replace(/wont/g, "w{on't|ill not}");
    s = s.replace(/won't/g, "w{on't|ill not}");
    s = s.replace(/Wont/g, "W{on't|ill not}");
    s = s.replace(/Won't/g, "W{on't|ill not}");

    // for will not
    s = s.replace(/will not/g, "w{on't|ill not}");
    s = s.replace(/Will not/g, "W{on't|ill not}");


    // for hasn't
    s = s.replace(/hasnt/g, "has{n't| not}");
    s = s.replace(/hasn't/g, "has{n't| not}");
    s = s.replace(/Hasnt/g, "Has{n't| not}");
    s = s.replace(/Hasn't/g, "Has{n't| not}");

    // for has not
    s = s.replace(/has not/g, "has{n't| not}");
    s = s.replace(/Has not/g, "Has{n't| not}");