Question

我想要做的是解析来自＆＃34;访问网站的网址＆＃34;链接

https://www.truelocal.com.au/business/index-partners/canberra

来源如下：

<span class="text-frame" ng-class="(vm.getHaveSecondaryWebsites()==true) ? 'with-aditional-item':''">
    <span ng-click="vm.openLink(vm.getReadableUrl(vm.getPrimaryWebsite()),'_blank')" role="button" tabindex="0">Visit website</span>
</span>

（我认为这是Angular？）

点击链接时，新标签会打开网址

我无法在源代码中看到解析它的网址（使用Python和Selenium）

有没有办法使用Python＆amp;硒？，

Answer 1

代码：

from selenium import webdriver

driver = webdriver.Chrome()
driver.get('https://www.truelocal.com.au/business/index-partners/canberra')
driver.find_element_by_xpath('//span[text()="Visit website"]').click()

# Switching to the 2nd newly opened tab
driver.switch_to.window(driver.window_handles[1])
print(driver.current_url)

# Switching to the 1st tab
driver.switch_to.window(driver.window_handles[0])
print(driver.current_url)

输出：

http://www.indexpartners.com.au/
https://www.truelocal.com.au/business/index-partners/canberra

使用Selenium WebDriver w Python从Angular JS链接中提取URL

1 个答案: