Laravel重定向到其他路线

Question

我有一个函数getLocation，该路由名为“search.location”，例如URL www.url.com/service/ny/slug。这显示了一个位置。

我现在想检查，如果位置可用。如果具有给定参数的位置不可用，我想要调用具有参数service和city的路径“search.servicecity”。该URL是www.url.com/service/ny/。如何使用参数调用路径？

public function getLocation($servicename, $city, $slug){
  $location = Location::where([
      ['slug','=',$slug],
      ['city','=',$city]
    ])->first();

  if(count($location)>0){
    return view('search.location')->with('servicename',$servicename)
                ->with('city',$city)->with('information','getLocation')
                ->with('slug',$slug)->with('location',$location);
  }else{
    //call search.servicecity with parameters $servicename and $city
  }
}