我正在学习postgreSQL，而且我对大多数人来说可能是一个非常基本的问题。我已经查看了很多不同的方法来使这个查询工作，但它不会根据我需要完成的工作。请注意，这不是一个家庭作业问题，而是来自不同的资源。问题是，有史以来最受欢迎的三篇文章是什么？哪些文章访问最多？将此信息显示为排序列表，其中最受欢迎的文章位于顶部。我到目前为止尝试过的查询语句是
news=> select articles.title, count(log.path) as art_view from log,
articles group by articles.title;
title | art_view
------------------------------------+----------
Bears love berries, alleges bear | 1677735
Bad things gone, say good people | 1677735
Balloon goons doomed | 1677735
Trouble for troubled troublemakers | 1677735
There are a lot of bears | 1677735
Media obsessed with bears | 1677735
Candidate is jerk, alleges rival | 1677735
Goats eat Google's lawn | 1677735
(8 rows)
news=> select articles.title, count(log.path) as art_view from log,
articles where status != '404 NOT FOUND' group by articles.title;
title | art_view
------------------------------------+----------
Bears love berries, alleges bear | 1664827
Bad things gone, say good people | 1664827
Balloon goons doomed | 1664827
Trouble for troubled troublemakers | 1664827
There are a lot of bears | 1664827
Media obsessed with bears | 1664827
Candidate is jerk, alleges rival | 1664827
Goats eat Google's lawn | 1664827
(8 rows)
news=> select articles.title, count(log.path) as art_view from articles,
log where status != '404 NOT FOUND' group by title;
title | art_view
------------------------------------+----------
Bears love berries, alleges bear | 1664827
Bad things gone, say good people | 1664827
Balloon goons doomed | 1664827
Trouble for troubled troublemakers | 1664827
There are a lot of bears | 1664827
Media obsessed with bears | 1664827
Candidate is jerk, alleges rival | 1664827
Goats eat Google's lawn | 1664827
(8 rows)
news=> select articles.title, count(log.path) as art_view from articles
join log on log.path where status !='404 NOT FOUND' group by title;
ERROR: argument of JOIN/ON must be type boolean, not type text
LINE 1: ...t(log.path) as art_view from articles join log on log.path
w...
^
news=> select articles.title, count(log.path) as art_view from articles
join log on substr(log.path) where status !='404 NOT FOUND' group by
title;
ERROR: function substr(text) does not exist
LINE 1: ...t(log.path) as art_view from articles join log on
substr(log...
^
HINT: No function matches the given name and argument types. You might
need to add explicit type casts.
news=>
感谢您的帮助。