Question

我通过SpriteKit创建游戏。在游戏中，每隔几秒就有一个球产生到屏幕上（通过功能），玩家必须将它们炸掉。现在，我想通过他的分数检查玩家等级，所以如果分数大于10，spawnBall功能将被执行两次（因此2个球将在屏幕上产生），依此类推。我尝试通过更新乐趣（将“读取”玩家得分并取决于得分将调用spawnBall函数）。不幸的是，当我这样做时，屏幕会在几秒钟内产生数百万个（或者说是）球（正如我所说，我希望它每隔几秒就调用一次这个功能，并在分数为X时增加通话）。我真的不知道该怎么做。这是我的代码：

override func update(_ currentTime: CFTimeInterval) {

    if (self.score <= 10){
        spawnBalls()
    }

    if (self.score > 10 && self.score <= 20){
        spawnBalls()
        spawnBalls()
    }

    if (self.score > 20){
        spawnBalls()
        spawnBalls()
        spawnBalls()
    }

    if (self.subscore == 3) {
        _ = randomBallColorToBlow()
        self.subscore = 0
    }
}

func spawnBalls() {
    let wait = SKAction.wait(forDuration: 1)
    let action = SKAction.run {
        self.createBall()
    }
    run(SKAction.repeatForever((SKAction.sequence([wait, action]))))
}

如何在不使用更新功能的情况下完成？

Answer 1

你通过在更新功能中调用它来每秒调用60次产卵球。尝试检查是否满足某个要求，以便在更新中升级到更高的生成率，但保持调用不在更新函数中。

private var upgradedToLevel2 = false
private var upgradedToLevel3 = false

//called somewhere probably in a start game func
spawnBalls(duration: 1.0)

override func update(_ currentTime: CFTimeInterval) {

    if (self.score > 10 && self.score <= 20) && !upgradedToLevel2 {
        //this prevents the if loop from running more than once
        upgradedToLevel2 = true 
        self.removeAction(forKey: "spawn")
        spawnBalls(duration: 0.5)
    }

    if (self.score > 20) && !upgradedToLevel3 {
        //this prevents the if loop from running more than once
        upgradedToLevel3 = true
        spawnBalls(duration: 0.33)
    }
}

func spawnBalls(duration: Double) {

    let wait = SKAction.wait(forDuration: duration)
    let action = SKAction.run { self.createBall() }
    let repeater = SKAction.repeatForever(SKAction.sequence([wait, action]))

    run(repeater, withKey: "spawn")
}

Answer 2

如前所述，你会多次产生球，需要将其分解。我建议使用Int而不是bool来跟踪关卡，以便能够处理“无限”数量的级别而不会产生“无限”的布尔变量

private var nextLevel = 0 //Level 0 allows us to spawn a ball on startup, so no need to call spawnBalls anywhere else

override func update(_ currentTime: CFTimeInterval) {

    if (self.score > 10 * nextLevel){
        self.removeAction(forKey: "spawn") //this prevents the if loop from running more than once
        nextLevel += 1
        spawnBalls(count:nextLevel,forDuration:1) //You can change the 1 here if you want to spawn balls at a faster speed,  I would recommend a variable that uses nextLevel in a forumula
    }
}

func spawnBalls(count:Int, forDuration duration:TimeInterval) {
    let range = 0..<count
    let wait = SKAction.wait(forDuration: duration)
    let action = SKAction.run {range.forEach{self.createBall()}}
    let repeater = SKAction.repeatForever(SKAction.sequence([wait, action]))
    removeAction(forKey:"spawn")
    run(repeater, withKey: "spawn")
}

更新内部多次快速调用函数

2 个答案: