Question

我想获取一个结构数组（带有date属性）并将该数组拆分为一个数组数组，其中每个子数组包含具有相同日历月中日期的项目。

我无法理解如何分割/分组等等......

我可以创建一个var array并按照我的方式迭代存放项目的数组，但我相信有更好的（更多功能，更Swifty）方法。

Answer 1

这里非常快：

struct Withdate {
  let value: String
  let month: Month
}

enum Month: Int {
  case Jan = 1, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec
}

let firstArray = [Withdate(value: "111", month: .Jan), Withdate(value: "112", month: .Jan), Withdate(value: "441", month: .Apr), Withdate(value: "442", month: .Apr), Withdate(value: "991", month: .Sep), Withdate(value: "992", month: .Sep)]

var objectsDict = [Month: [Withdate]]()

firstArray.forEach { if objectsDict[$0.month] == nil { objectsDict[$0.month] = [Withdate]()  }
objectsDict[$0.month]!.append($0) }
let finalArray = Array(objectsDict.values.map{ $0 })

print(finalArray) // will return:

[[main.Withdate(value: "111", month: main.Month.Jan), main.Withdate(value: "112", month: main.Month.Jan)], [main.Withdate(value: "441", month: main.Month.Apr), main.Withdate(value: "442", month: main.Month.Apr)], [main.Withdate(value: "991", month: main.Month.Sep), main.Withdate(value: "992", month: main.Month.Sep)]]

将结构数组（带日期）拆分为按月分组的2D数组

1 个答案: