看看这段代码，它是Tic Tac Toe的游戏 游戏结束后，程序会询问用户是否要再次播放，如果是，则该功能再次运行。但是，数组值在全局声明时仍保持更新状态。该数组必须全局声明，因为它在多个函数中使用。当用户选择再次播放选项时，有没有办法将数组的值重置为原始值？
#include <iostream>
#include <string>
using namespace std;
void contents(); //function to draw the tic tac toe board
char letters[9] = {'a','b','c','d','e','f','g','h','i'}; //array containing
the default characters of the board
string check(); //function to check whether the game is ongoing or has ended
in a win or draw
string result; // string telling us whether the game is ongoing or has ended
in a win or draw
void contents()
{
cout <<endl<<endl<<endl<<" Tic Tac Toe"<<endl<<endl<<endl;
cout << endl;
cout << " | | " << endl;
cout << " " << letters[0] << " | " << letters[1] << " | " << letters[2]
<< endl;
cout << " | | " << endl;
cout << "----- ----- -----" << endl;
cout << " | | " << endl;
cout << " " << letters[3] << " | " << letters[4] << " | " << letters[5]
<< endl;
cout << " | | " << endl;
cout << "----- ----- -----" << endl;
cout << " | | " << endl;
cout << " " << letters[6] << " | " << letters[7] << " | " << letters[8]
<< endl;
cout << " | | " << endl << endl;
}
int main()
{
char selection1; //selection of the mark chosen by player 1 (X or O)
int player = 1;
char mark;//X or O
char selection2; //selection of the character to replace in the array chosen
by the players
char invalid; //character to enter if the user selects a character that
isn't present in the array
string choice;
while(selection1!='X' || selection1!='Y')
{
cout<<"Make your selection player 1 (X or O): ";
cin>>selection1;
if (selection1=='X' || selection1=='O')
break;
else
cout<<"Make a valid selection, press enter to select again"<<endl;
cin.ignore();
cin.get();
}
do
{
player=(player%2)?1:2;
if(selection1 =='X')
mark = (player == 1) ? 'X' : 'O';
else if (selection1=='O')
mark = (player == 1) ? 'O' : 'X';
contents();
cout << "Player " << player << ", enter a letter: ";
cin >> selection2;
if (selection2 == 'a' && letters[0] == 'a')
letters[0] = mark;
else if (selection2 == 'b' && letters[1] == 'b')
letters[1] = mark;
else if (selection2 == 'c' && letters[2] == 'c')
letters[2] = mark;
else if (selection2 == 'd' && letters[3] == 'd')
letters[3] = mark;
else if (selection2 == 'e' && letters[4] == 'e')
letters[4] = mark;
else if (selection2 == 'f' && letters[5] == 'f')
letters[5] = mark;
else if (selection2 == 'g' && letters[6] == 'g')
letters[6] = mark;
else if (selection2 == 'h' && letters[7] == 'h')
letters[7] = mark;
else if (selection2 == 'i' && letters[8] == 'i')
letters[8] = mark;
else
{
cout<<"Invalid move, press enter to continue: ";
cin.ignore();
cin.get();
player--;
}
result=check();
player++;
}while(result=="Ongoing");
contents();
if(result=="Over")
{
cout<<"Player "<<--player<<" wins ";
cin.ignore();
cin.get();
cout<<"Do you want to play again?";
cin>>choice;
if (choice =="Yes")
main();
}
else
{
cout<<"Draw";
cin.ignore();
cin.get();
cout<<"Do you want to play again?";
cin>>choice;
if (choice =="Yes")
main();
}
return 0;
}
string check()
{
if (letters[0] == letters[1] && letters[1] == letters[2])
return "Over";
else if (letters[3] == letters[4] && letters[4] == letters[5])
return "Over";
else if (letters[6] == letters[7] && letters[7] == letters[8])
return "Over";
else if (letters[0] == letters[3] && letters[3] == letters[6])
return "Over";
else if (letters[1] == letters[4] && letters[4] == letters[7])
return "Over";
else if (letters[2] == letters[5] && letters[5] == letters[8])
return "Over";
else if (letters[0] == letters[4] && letters[4] == letters[8])
return "Over";
else if (letters[2] == letters[4] && letters[4] == letters[6])
return "Over";
else if (letters[0] != 'a' && letters[1] != 'b' && letters[2] != 'c'
&& letters[3] != 'd' && letters[4] != 'e' && letters[5] != 'f'
&& letters[6] != 'g' && letters[7] != 'h' && letters[8] != 'i')
return "Draw";
else
return "Ongoing";
}
答案 0 :(得分：2)
显而易见的方法是编写一个新功能，完全符合您的要求，即将letters[0]设置为'a'等。
您稍后可能会了解课程。一个类包含多个函数，还包含多个数据成员。这样一个类的每个实例都称为一个对象，并且您将每一轮游戏都实现为一个新对象。