Question

我在PHP中有以下数组（称为$ available_dates）：

Array
(
    [0] => 2017-11-28
    [1] => 2017-11-29
    [2] => 2017-11-30
)

此数组传递给查询API的函数，以获取与这些日期相关的游览时间：

for($a=0;$a<count($available_dates);$a++) {

    $url = "HTTP API END POINT";
    $json = json_decode(get_JSON($url),true);
    $total_records = intval($json['total']);

    $tour_times = array();

    for($b=0;$b<$total_records;$b++) {

       //$tour_time is a string e.g. 11:30 AM
       $tour_time = $json['item'][$b]['time'];

       //Keep track, add to my time array
       $tour_times[] = $tour_time;
    }

    //Issue is here
    $available_dates[$a][] = $tour_times;


}

这会在上面指定的行产生以下错误：

[] operator not supported for strings in

我想要创建的是，请原谅我糟糕的格式和表示：

Array
    (
        [0] => 2017-11-28
               array(0 => '12:00 PM', 1 => '2:00 PM')
        [1] => 2017-11-29
               array(0 => '11:00 PM', 1 => '10:00 PM')
        [2] => 2017-11-30
               array(0 => '9:00 AM', 1 => '2:00 PM')
    )

Answer 1

您需要将基础$ available_dates结构更改为其中之一：

$available_dates = array(
    '2017-11-28'=>array(),
    '2017-11-29'=>array(),
    '2017-11-30'=>array(),
);

或

$available_dates = Array
(
    [0] => array('date'=>'2017-11-28' , 'times'=>array())
    [1] => array('date'=>'2017-11-29' , 'times'=>array())
    [2] => array('date'=>'2017-11-30' , 'times'=>array())
)

purpuse是在内部数组中保存“times”。

然后当你迭代时，$ available_dates从密钥中获取日期（选项1）或从内部“日期”新密钥中获取日期（选项2），并且对于API的每个json结果...输入“times”数组

foreach($available_dates AS $k=>$date) {

    $url = "HTTP API END POINT";
    $json = json_decode(get_JSON($url),true);
    $total_records = intval($json['total']);

    $tour_times = array();

    for($b=0;$b<$total_records;$b++) {
         //$tour_time is a string e.g. 11:30 AM
         $tour_time = $json['item'][$b]['time'];

         //Keep track, add to my time array
         $tour_times[] = $tour_time;
    }

    //option 1
    $available_dates[$k] = $tour_times;

    // option 2
    $available_dates[$k]['times'] = $tour_times;
}

Answer 2

您可以添加以下内容：

$previous_date = $available_dates[$a];

$available_dates[$a] = array();

$available_dates[$a][] = $previous_date;

$merge = array_merge($available_dates[$a], $tour_times);

将数组添加到现有PHP数组元素

2 个答案: