我试图通过其中一个键的值来获取数组中的对象。
数组:
{
"privileges" :
[
{
"resource" : "login" ,
"actions": ["true"]
},
{
"resource": "user" ,
"actions": ["create","read"]
}
]
}
答案 0 :(得分:2)
let obj = {
"privileges" :
[
{
"resource" : "login" ,
"actions": ["true"]
},
{
"resource": "user" ,
"actions": ["create","read"]
}
]
}
function filterValue(value) {
return obj["privileges"].filter((object) => {
return object["resource"] == value
})
}
console.log(filterValue("user"))
答案 1 :(得分:0)
目前还不清楚你在问什么,但是搜索对象属性值将是这样的Ramda:
const a = {
"privileges": [
{
"resource" : "login" ,
"actions": ["true"]
},
{
"resource": "user" ,
"actions": ["create","read"]
}
]
}
R.find(R.propEq("resource", "login"), a.privileges);
答案 2 :(得分:0)
您可以使用find方法:
const a = {
"privileges": [
{
"resource" : "login" ,
"actions": ["true"]
},
{
"resource": "user" ,
"actions": ["create","read"]
}
]
};
var objFound = a.privileges.find(obj => obj.resource === "user");