Question

我正在做这样的事情：

import pathlib

p = pathlib.Path("temp/").mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    f.write(result)

错误消息：AttributeError：'NoneType'对象没有属性'open'

显然，根据错误消息，mkdir会返回None。

Jean-Francois Fabre提出了这一更正：

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    ...

这会触发新的错误消息：

文件“/Users/user/anaconda/lib/python3.6/pathlib.py”，第1164行，处于打开状态       开瓶器= self._opener）
  TypeError：需要一个整数（得到类型str）

Answer 1

你可以尝试：

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
fn = "test.txt" # I don't know what is your fn
filepath = p / fn
with filepath.open("w", encoding ="utf-8") as f:
    f.write(result)

您不应该将字符串作为路径。这是您的对象filepath，其方法为open。

source

Answer 2

您可以直接初始化filepath并为parent属性创建父目录：

from pathlib import Path

filepath = Path("temp/test.txt")
filepath.parent.mkdir(parents=True, exist_ok=True)

with filepath.open("w", encoding ="utf-8") as f:
    f.write(result)

Answer 3

也许这是您想要做的最短的代码。

import pathlib

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
(p / ("temp." + fn)).write_text(result, encoding="utf-8")

在大多数情况下，通过使用write_text()甚至不需要open（）上下文。

Answer 4

The pathlib module offers an open method that has a slightly different signature to the built-in open function.

pathlib:

Path.open(mode='r', buffering=-1, encoding=None, errors=None, newline=None)

The built-in:

open(file, mode='r', buffering=-1, encoding=None, errors=None, newline=None, closefd=True, opener=None)

In the case of this p = pathlib.Path("temp/") it has created a path p so calling p.open("temp."+fn, "w", encoding ="utf-8") with positional arguments (not using keywords) expects the first to be mode, then buffering, and buffering expects an integer, and that is the essence of the error; an integer is expected but it received the string 'w'.

This call p.open("temp."+fn, "w", encoding ="utf-8") is trying to open the path p (which is a directory) and also providing a filename which isn't supported. You have to construct the full path, and then either call the path's open method or pass the full path into the open built-in function.

使用pathlib在python中创建新文件夹并将文件写入其中

4 个答案: