我需要帮助解决问题。实际上，我不知道是否可以直接在SQL中解决它。
我有一份作品清单。每件作品都有一个开始日期和结束日期，格式为
YYYY/MM/DD HH24:MI:SS
我需要计算这些工作的成本，小时价格取决于工作完成的时间间隔：
Nigth time: 22:00 to 6:00, for example: 20 €/h
Normal time: the rest 17 €/h
所以，如果我有这样的样本：
wo start end
21 2017/11/16 21:25:00 2017/11/16 22:55:00
22 2017/11/17 05:45:00 2017/11/17 07:05:00
23 2017/11/18 23:00:00 2017/11/19 1:10:00
24 2017/11/17 18:00:00 2017/11/17 19:00:00
我需要计算22h和6h之间的日期间隔，其余的乘以相应的价格
wo rest(minutes) night(minutes)
21 35 55
22 15 65
23 0 130
24 1 0
提前感谢您的帮助。
答案 0 :(得分：3)
嘿。如果你真的希望它:)
第五条记录（从2016-10-30开始）已被添加用于测试目的。
SQL> with
2 src as (select timestamp '2017-11-16 21:25:00' b, timestamp '2017-11-16 22:55:00' f from dual union all
3 select timestamp '2017-11-17 05:45:00' b, timestamp '2017-11-17 07:05:00' f from dual union all
4 select timestamp '2017-11-18 23:00:00' b, timestamp '2017-11-19 1:10:00' f from dual union all
5 select timestamp '2017-11-17 18:00:00' b, timestamp '2017-11-17 19:00:00' f from dual union all
6 select timestamp '2016-10-30 00:00:00' b, timestamp '2016-11-03 23:00:00' f from dual),
7 srd as (select b, f, f - b t from src),
8 mmm as (select min(trunc(b)) b, max(trunc(f)) f from src),
9 rws as (select b + 6/24 + rownum - 1 b, b + 22/24 + rownum - 1 f from mmm connect by level <= f - b + 1),
10 mix as (select s.b, s.f, s.t, r.b rb, r.f rf from srd s, rws r where s.f >= r.b (+) and r.f (+) >= s.b),
11 clc as (select b, f, t, nvl(numtodsinterval(sum((least(f, rf) + 0) - (greatest(b, rb) + 0)), 'DAY'), interval '0' second) d from mix group by b, f, t)
12 select
13 to_char(b, 'dd.mm.yyyy hh24:mi') as "datetime begin",
14 to_char(f, 'dd.mm.yyyy hh24:mi') as "datetime finish",
15 cast(t as interval day to second(0)) as "total time",
16 cast(d as interval day to second(0)) as "daytime",
17 cast(t - d as interval day to second(0)) as "nighttime"
18 from
19 clc
20 order by
21 1, 2;
datetime begin datetime finish total time daytime nighttime
------------------ ------------------ -------------- -------------- --------------
16.11.2017 21:25 16.11.2017 22:55 +00 01:30:00 +00 00:35:00 +00 00:55:00
17.11.2017 05:45 17.11.2017 07:05 +00 01:20:00 +00 01:05:00 +00 00:15:00
17.11.2017 18:00 17.11.2017 19:00 +00 01:00:00 +00 01:00:00 +00 00:00:00
18.11.2017 23:00 19.11.2017 01:10 +00 02:10:00 +00 00:00:00 +00 02:10:00
30.10.2016 00:00 03.11.2016 23:00 +04 23:00:00 +03 08:00:00 +01 15:00:00
答案 1 :(得分：0)
另一种方法是更多强力，但它允许将间隔配置与报告区分开来。 它进入了三个方面：
1）定义当天aech分钟的费率类型（如果需要，更改粒度）
create table day_config as
with helper as (
select
rownum -1 minute_id
from dual connect by level <= 24*60),
helper2 as (
select
minute_id,
trunc(minute_id/60) hour_no,
mod(minute_id,60) minute_no
from helper)
select
minute_id,hour_no, minute_no,
case when hour_no >= 22 or hour_no <= 5 then 0 else 1 end rate_id
from helper2;
select * from day_config order by minute_id;
MINUTE_ID HOUR_NO MINUTE_NO RATE_ID
---------- ---------- ---------- ----------
0 0 0 0
1 0 1 0
2 0 2 0
3 0 3 0
4 0 4 0
5 0 5 0
6 0 6 0
7 0 7 0
8 0 8 0
9 0 9 0
此处rate_id表示nigth，rate_id表示一天。 优点是，您可以根据需要引入尽可能多的费率类型。
2）扩展所需时间间隔的配置，例如到了整整一年。 所以现在我们在一年中的每一分钟都有配置，即适用的费率。
create or replace view year_config as
select my_date + MINUTE_ID / (24*60) minute_ts , MINUTE_ID, HOUR_NO, MINUTE_NO, RATE_ID from day_config
cross join
(select DATE '2017-01-01' + rownum -1 as my_date from dual connect by level <= 365)
order by 1,2;
select * from (
select * from year_config
order by 1)
where rownum <= 5;
MINUTE_TS MINUTE_ID HOUR_NO MINUTE_NO RATE_ID
------------------- ---------- ---------- ---------- ----------
01-01-2017 00:00:00 0 0 0 0
01-01-2017 00:01:00 1 0 1 0
01-01-2017 00:02:00 2 0 2 0
01-01-2017 00:03:00 3 0 3 0
01-01-2017 00:04:00 4 0 4 0
3）报告就像加入我们的配置表一样简单，限制了RATE中的间隔（半开）和分组。
select b, f,RATE_ID, count(*) minute_cnt
from tst join year_config c on c.MINUTE_TS >= tst.b and c.MINUTE_TS < tst.f
group by b, f,RATE_ID
order by b, f,RATE_ID;
B F RATE_ID MINUTE_CNT
------------------- ------------------- ---------- ----------
16-11-2017 21:25:00 16-11-2017 22:55:00 0 55
16-11-2017 21:25:00 16-11-2017 22:55:00 1 35
17-11-2017 05:45:00 17-11-2017 07:05:00 0 15
17-11-2017 05:45:00 17-11-2017 07:05:00 1 65
17-11-2017 18:00:00 17-11-2017 19:00:00 1 60
18-11-2017 23:00:00 19-11-2017 01:10:00 0 130