Question

有没有办法在下拉框in_array中设置所选项目。但是Selected =“selected”对我不起作用。只有少数选择的值显示下拉并且没有被选中

我尝试了以下代码

List

这里：

<label for="assignedto">Assigned to</label>
@foreach($menu as $menus)
   <?php
     $assignedid=$menus->assigned_to;
     $assid[]=explode(',',$assignedid);

   ?>
@endforeach
<?php $maxcount= count($assid); echo '<pre>';print_r($assid); ?>
      <select id="framework1" name="Roles[]" multiple class="form-control" >
        <?php $a= 0;?>          
          @foreach($roles as $id=>$name)
       <?php $newcount=count($assid[$a]);?>
       <option value="{{$id}}"@if(in_array($id, $assid[$a]))selected="selected"@endif>{{$name}}</option>
<?php  
$a++; 
if($a==$maxcount) break; 
?>
@endforeach

角色数组是：

$assid=Array
(
    [0] => Array
        (
            [0] => 6
            [1] => 2
            [2] => 3
        )

    [1] => Array
        (
            [0] => 4
            [1] => 5
            [2] => 6
        )

    [2] => Array
        (
            [0] => 6
        )

    [3] => Array
        (
            [0] => 2
            [1] => 3
        )

)

对于第一次迭代，我想选择id 4,5,6意味着经理，主管，测试人员应该被选中，同样第二次迭代4,5,6选择等但选择多个选择对我不起作用。请帮助我。非常感谢

Answer 1

我希望您需要重新编写下面的链接：

<select id="framework1" name="Roles[]" multiple class="form-control" >              
   @foreach($roles as $id=>$name)   
        <option value="{{$id}}" 
         @if(in_array($id, $assid[$a])) 
            selected="selected"
         @endif
         >{{$name}}</option>
   @endforeach
</select>

Answer 2

使用可以使用三元运算符代替＆＃34;如果＆＃34; -

<option value="{{$id}}" <?php echo ((in_array($id, $assid[$a])) ? 'selected="selected"':'')?> >{{$name}}</option>

Answer 3

重写您的代码如下： -

<label for="assignedto">Assigned to</label>
<?php $assid = []; // declare array ?>
@foreach($menu as $menus)
<?php
    if(!empty($menus->assigned_to)){ // check if assigned_to key exist in array
        $assignedid=$menus->assigned_to;        
        $assid[]=explode(',',$assignedid);  
    }
?>
@endforeach          

<?php   
  if(!empty($assid)){  
        $assid = call_user_func_array('array_merge', $assid); // It will shift all array elements up one level
  }
  $assid = empty($assid) ? [] : array_combine($assid, $assid); // rewrite this line

?>    

<select id="framework1" name="Roles[]" multiple class="form-control" >              
   @foreach($roles as $id=>$name)   
        <option value="{{$id}}"@if(in_array($id, $assid))selected="selected"@endif>{{$name}}</option>
   @endforeach
</select>

选择不工作in_array php

3 个答案: