Question

假设我有两个列表：

list_one = ["Alex", "Alex", "John", "Alex", "John", "John"]
list_two = ["Hi", "Are you there?", "Hello Alex!", "How are you John?", "I am good Alex", "How about yourself?"]

我希望在列表一中将相同的项目合并在一起（将此列表称为三个）

list_one = ["Alex", "Alex", "John", "Alex", "John", "John"]
list_three = ["Alex", "John", "Alex", "John"]

并列出两个转到列表四，它遵循合并第一个列表中的项目的“模式”：

list_two = ["Hi", "Are you there?", "Hello Alex!", "How are you John?", "I am good Alex", "How about yourself?"]
list_four = ["Hi Are you there?", "Hello Alex!", "How are you John?", "I am good Alex How about yourself?"]

我该怎么办？我发现了这个：Remove adjacent duplicate elements from a list，但它没有处理多个列表，我不想从第二个列表中删除项目。

编辑：我找到了一个帖子，我可以在列表中获取项目的所有实例，他们使用的代码是：

def all_indices(value, qlist):
indices = []
idx = -1
while True:
    try:
        idx = qlist.index(value, idx+1)
        indices.append(idx)
    except ValueError:
        break
return indices

现在如果我为我的代码执行此操作，我会得到两个列表：

Alex = [0,1,3]
John = [2,4,5]

但是，如何编写一个将list_two [0]和list_two [1]组合在一起的函数？或者如果Alex = [0,1,2,3,4,5]，我怎么能将所有这些组合成一个列表中的一个项呢？

Answer 1

另一个groupby解决方案：

from itertools import groupby

list_one = ["Alex", "Alex", "John", "Alex", "John", "John"]
list_two = ["Hi", "Are you there?", "Hello Alex!", "How are you John?", "I am good Alex", "How about yourself?"]

l2iter = iter(list_two)
list_three, list_four = zip(*((key, ' '.join(next(l2iter) for whatever in grp)) for key, grp in groupby(list_one)))

合并列表中的项目，如果它们相似并且彼此相邻

1 个答案: