我有两个html选择元素,第一个被禁用,只有当用户从第一个选择中选择一个选项时才会启用。考虑我们在第一个选择中有2个选项 - > a,b如果用户选择a:在第二个选择选项中应该是:a1,a2如果用户选择b:在第二个选择选项中应该是:b1,b2 ...我不知道我做错了这两个选择选项之间存在冲突!!!
<select id="main-category" required>
<option disabled selected> choose one option </option>
<option value="a"> a </option>
<option value="b"> b </option>
</select>
<select id="sub-category" required disabled> </select>
<!-- empty select -->
<script>
document.getElementById("main-category").onchange = function() {
document.getElementById('sub-category').disabled = false;
var opt0 = document.createElement('option');
var opt1 = document.createElement('option');
if (this.value == 'a') {
//first remove all previous options then add new ones
if (document.getElementById('sub-category').getElementsByTagName('option')[0]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[0];
document.getElementById('sub-category').removeChild(opt);
}
if (document.getElementById('sub-category').getElementsByTagName('option')[1]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[1];
document.getElementById('sub-category').removeChild(opt);
}
opt0.value = "a1";
opt0.innerHTML = "a1";
opt1.value = "a2";
opt1.innerHTML = "a2";
document.getElementById('sub-category').appendChild(opt0);
document.getElementById('sub-category').appendChild(opt1);
} else if (this.value == 'b') {
//first remove all previous options then add new ones
if (document.getElementById('sub-category').getElementsByTagName('option')[0]) { //check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[0];
document.getElementById('sub-category').removeChild(opt);
}
if (document.getElementById('sub-category').getElementsByTagName('option')[1]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[1];
document.getElementById('sub-category').removeChild(opt);
}
opt0.value = "b1";
opt0.innerHTML = "b1";
opt1.value = "b2";
opt1.innerHTML = "b2";
document.getElementById('sub-category').appendChild(opt0);
document.getElementById('sub-category').appendChild(opt1);
}
};
</script>
答案 0 :(得分:0)
每次在第一个选项中进行选择时,您需要做的就是清除第二个下拉列表中的先前条目。
<select id="main-category" required>
<option disabled selected> choose one option </option>
<option value="a"> a </option>
<option value="b"> b </option>
</select>
<select id="sub-category" required disabled> </select>
<!-- empty select -->
<script>
document.getElementById("main-category").onchange = function() {
// Clear out the second list before adding new items to it
document.getElementById('sub-category').innerHTML = "";
// *******************************************************
document.getElementById('sub-category').disabled = false;
var opt0 = document.createElement('option');
var opt1 = document.createElement('option');
if (this.value == 'a') {
//first remove all previous options then add new ones
if (document.getElementById('sub-category').getElementsByTagName('option')[0]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[0];
document.getElementById('sub-category').removeChild(opt);
}
if (document.getElementById('sub-category').getElementsByTagName('option')[1]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[1];
document.getElementById('sub-category').removeChild(opt);
}
opt0.value = "a1";
opt0.innerHTML = "a1";
opt1.value = "a2";
opt1.innerHTML = "a2";
document.getElementById('sub-category').appendChild(opt0);
document.getElementById('sub-category').appendChild(opt1);
} else if (this.value == 'b') {
//first remove all previous options then add new ones
if (document.getElementById('sub-category').getElementsByTagName('option')[0]) { //check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[0];
document.getElementById('sub-category').removeChild(opt);
}
if (document.getElementById('sub-category').getElementsByTagName('option')[1]) {//check if there is a option then remove it
var opt = document.getElementById('sub-category').getElementsByTagName('option')[1];
document.getElementById('sub-category').removeChild(opt);
}
opt0.value = "b1";
opt0.innerHTML = "b1";
opt1.value = "b2";
opt1.innerHTML = "b2";
document.getElementById('sub-category').appendChild(opt0);
document.getElementById('sub-category').appendChild(opt1);
}
};
</script>
&#13;
但是,除此之外,您的代码需要进行相当多的清理,因为当您已经找到它时,您不应该一遍又一遍地扫描文档以查找要使用的元素。之前。这非常浪费。
此外,.innerHTML
用于传递包含HTML的字符串,以便HTML解析器可以解析字符串并相应地更新DOM。您只是设置了没有HTML的纯字符串,因此您应该使用.textContent
代替,它不会调用HTML解析器并且效率更高。
下一步(仅供参考),如果您希望option
的值与显示给用户的文字相同,则无需设置value
那个option
。默认情况下,value
是option
元素的内容。
实际上,只需根据list1中选择的选项的第一个字母在list2中创建新选项,就可以简化整个操作。
// Get references to the elements you'll be working with just once:
var list1 = document.getElementById("main-category");
var list2 = document.getElementById('sub-category');
list1.onchange = function() {
list2.disabled = false;
var newHTML = ""; // A string that will contain the new HTML for the second list
// Loop the amount of times we find <option> elements in list one, but start
// at the second one to account for the first one, which isn't really a true choice
for(var i = 1; i < list1.querySelectorAll("option").length; i++){
// Build up a string that the new option should be made from using the
// first character from the option found in list 1
newHTML += '<option>' + list1.value.substr(0,1) + i + '</option>';
}
// By setting a new value for .innerHTML, the old values get thrown out.
list2.innerHTML = newHTML;
};
&#13;
<select id="main-category" required>
<option disabled selected> choose one option </option>
<option>a</option>
<option>b</option>
</select>
<select id="sub-category" required disabled> </select>
&#13;