我有一个listview,当我在on on中调用SQL查询内部联接时,它没有做任何事情也没有发生错误
public Cursor getBankBranch() {
Cursor cursor;
SQLiteDatabase db = mDbHelper.getReadableDatabase();
String selectQuery = "SELECT * FROM " + DataEntry.BRANCH_TABLE_NAME + " INNER JOIN "
+ DataEntry.BANK_TABLE_NAME + " ON "
+ DataEntry.BANK_TABLE_NAME + "." + DataEntry.COLUMN_BANK_ID + " = "
+ DataEntry.BRANCH_TABLE_NAME + "." + DataEntry.COLUMN_BRANCH_BANK_ID;
cursor = db.rawQuery(selectQuery, null);
cursor.moveToFirst();
cursor.close();
return cursor;
}
这是表的内容
String SQL_CREATE_BANK_TABLE = "CREATE TABLE " + DataEntry.BANK_TABLE_NAME + " ("
+ DataEntry.COLUMN_BANK_ID + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ DataEntry.COLUMN_BANK_NAME + " TEXT );";
String SQL_CREATE_BRANCH_TABLE = "CREATE TABLE " + DataEntry.BRANCH_TABLE_NAME + " ("
+ DataEntry.COLUMN_BRANCH_ID + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ DataEntry.COLUMN_BRANCH_NAME + " TEXT , "
+ DataEntry.COLUMN_BRANCH_NUMBER + " TEXT , "
+ DataEntry.COLUMN_BRANCH_ADDRESS + " TEXT, "
+ DataEntry.COLUMN_BRANCH_BANK_ID + " INTEGER );";
// Execute the SQL statement
db.execSQL(SQL_CREATE_BANK_TABLE);
db.execSQL(SQL_CREATE_BRANCH_TABLE);
答案 0 :(得分:0)
您只是将光标指向结果集,然后在关闭它之后将其移动到第一个结果,但您实际上并未使用它。
让它发挥作用的步骤
进行选择查询
String selectQuery = "SELECT ..."
执行查询以获取游标
cursor = db.rawQuery(selectQuery, null);
创建一个cursorAdapter
MyCursorAdapter adapter = new MyCursorAdapter(this, cursor);
设置ListView的适配器
list.setAdapter(adapter);