Question

这是我的代码：

from __future__ import print_function

import random

from random import shuffle
from random import randint

class ship:
    def __init__(self):
        self.database_scientific = 100
        self.database_cultural = 100

def move_on(self):


    def _do_damage(self):
        self = self - randint(5,30)

        print(module)

    system_list = [
        'scientific database', 
        'cultural database'
    ]

    system_list_damaged = {
        'scientific database': _do_damage(self.database_scientific),
        'cultural database': _do_damage(self.database_cultural)
    }

    if randint(0,10) >= 1:
        encounter_type = randint(1,4)
        vulnerable_system = system_list[0]
        vulnerable_system_number_two = system_list[1]
        if encounter_type == 1:
            print("\n[1] Allow it to hit %s. \n[2] Rotate so it hits another part of the ship." % vulnerable_system)

            choice = raw_input("\n> ")

            if choice == 1 and vulnerable_system == "surface probes":
                print("\nThe asteroid crashes into the ship and knocks one of the surface probes loose.")
                self.surface_probes = self.surface_probes - 1
            elif choice == 1:
                print("\nThe asteroid crashes into the %s causing irreparable damage." % vulnerable_system)
                for vulnerable_system in system_list_damaged.keys():
                    system_list_damaged[vulnerable_system](self)
                    break
s = ship()
s.move_on()

当我初始化move_on（）定义时没有明确告知它时正在执行_do_damage（）。任何人都能解释为什么会这样吗？我找不到一个好的答案或解决方案。我最初在move_on（）之外有_do_damage（），但这不允许我调用_do_damage（）定义......

Answer 1

您将函数调用存储为字典中的值。 存储函数调用的返回值，不是函数本身。要调用存储在字典中的函数，

system_list_damaged = {
    'scientific database': _do_damage,
}

# call: 
system_list_damaged['scientific database'](self.database_scientific)

从system_list中选择一个随机列表元素（根据您的评论），

from random import choice
element = choice(system_list)

现在，为了简化这一切，你可以这样做：

from random import choice

system_list_damaged = {
    'scientific database': [_do_damage, self.database_scientific]
    'cultural database': [_do_damage, self.database_cultural]
}
# and to call a random one,
function_to_call = choice(system_list_damaged.keys())
system_list_damaged[function_to_call][0](function_to_call[1])

Python没有指示时执行定义

1 个答案: