Question

我需要在一个表中插入多个表和多行。

让我们说有3张桌子

1：主题表

+----+-------------+-------+
| ID |   Subject   | Class |
+----+-------------+-------+
|  1 | English     |     1 |
|  2 | Mathematics |     1 |
|  3 | Sciences    |     1 |
|  4 | English     |     2 |
|  5 | Mathematics |     2 |
+----+-------------+-------+

2：月份表

+----+-------+
| ID | Month |
+----+-------+
|  1 | Oct   |
|  2 | Nov   |
|  3 | Desc  |
+----+-------+

2：用户表

+----+------+---------+
| ID | Name | ClassID |
+----+------+---------+
|  1 | XerK |    1    |
|  2 | cdya |    1    |
|  3 | nija |    2    |
|  4 | Sara |    2    |
|  5 | Noda |    2    |
+----+------+---------+

现在我需要在此表中插入所有这些

结果表

+----+---------+----------------+---------+-------+-------+-------+
| ID | userID  |   subjectID    | MonthID  | Exam1 | Exam2 | Exam3 |
+----+---------+----------------+---------+-------+-------+-------+
|  1 | 1(xerk) | 1(English)     | 1(oct)  | NULL  | NULL  | NULL  |
|  2 | 1(xerk) | 2(Mathematics) | 1(oct)  | NULL  | NULL  | NULL  |
|  3 | 1(xerk) | 3(Sciences)    | 1(oct)  | NULL  | NULL  | NULL  |
|  4 | 1(xerk) | 1(English)     | 2(nov)  | NULL  | NULL  | NULL  |
|  5 | 1(xerk) | 2(Mathematics) | 2(nov)  | NULL  | NULL  | NULL  |
|  6 | 1(xerk) | 3(Sciences)    | 2(nov)  | NULL  | NULL  | NULL  |
|  7 | 1(xerk) | 1(English)     | 3(desc) | NULL  | NULL  | NULL  |
|  8 | 1(xerk) | 2(Mathematics) | 3(desc) | NULL  | NULL  | NULL  |
|  9 | 4(Sara) | 3(Sciences)    | 3(desc) | NULL  | NULL  | NULL  |
| 10 | 4(Sara) | 4(English)     | 1(oct)  | NULL  | NULL  | NULL  |
| 11 | 4(Sara) | 5(Mathematics) | 1(oct)  | NULL  | NULL  | NULL  |
| 12 | 4(Sara) | 4(English)     | 2(nov)  | NULL  | NULL  | NULL  |
| 13 | 4(Sara) | 5(Mathematics) | 2(nov)  | NULL  | NULL  | NULL  |
| 14 | 4(Sara) | 4(English)     | 3(desc) | NULL  | NULL  | NULL  |
| 15 | 4(Sara) | 5(Mathematics) | 3(desc) | NULL  | NULL  | NULL  |
+----+---------+----------------+---------+-------+-------+-------+

如何在页面PHP中通过一个按钮插入所有这些？需要插入每个用户都有subjectID和MonthID。

解决方案

INSERT INTO results 
    (Col1, Col2, Col3, Col4, Col5, Col6)
SELECT 
    users.Col1, subjects.Col2, months.Col3, 0, 0, 0
FROM
    (SELECT Col1 FROM users) as users
CROSS JOIN
    (SELECT Col2 FROM subjects) as subjects
CROSS JOIN
    (SELECT Col3 FROM months) as months

我找到了答案，但我需要在结果表中插入新的成员数据而不重复旧成员。

在一个表中插入多个表和多个行

0 个答案: