Question

我希望该用户通过其用户ID更新自己的数据。我不希望它会在网址中显示，所以我试着这样做：

<?php
session_start();
if (isset($_SESSION['id'])){
    $userId = $_SESSION['id'];
}
else {
    header('Location: login_sys.php');
  die();
}

include_once('/var/www/html/private/db_credentials.php');
$db = mysql_connect ("$servername", "$username", "$password", "$dbname") or die("Kann nicht mit DB verbinden.!");

//Wenn eingegeben
if (isset ($_POST['submit'])) {
      $betrieb = $_POST['betrieb'];
    $anschrift = $_POST['ort'];
    $apartner = $_POST['apartner'];
    $praktika = $_POST['praktika'];
    //Was wurde eingegeben

    //
    $query = "UPDATE nutzer SET betrieb='$betrieb', ort='$ort', apartner='$apartner', praktika='$praktika' WHERE id='$userId' ";
    mysqli_query($db, $query, $sql);
}

?>

以下是表格：

<form action="bearbeitung_checker.php" method="POST">
  <div class="mdl-textfield mdl-js-textfield mdl-textfield--floating-label">
    <input class="mdl-textfield__input" type="text" id="sample3" name="betrieb">
    <label class="mdl-textfield__label" for="sample3">Betrieb...</label>
  </div>


<!-- Textfield with Floating Label -->


  <div class="mdl-textfield mdl-js-textfield mdl-textfield--floating-label">
    <input class="mdl-textfield__input" type="text" id="sample3" name="ort">
    <label class="mdl-textfield__label" for="sample3">Anschrift...</label>
  </div>


<!-- Textfield with Floating Label -->


  <div class="mdl-textfield mdl-js-textfield mdl-textfield--floating-label">
    <input class="mdl-textfield__input" type="text" id="sample3" name="apartner">
    <label class="mdl-textfield__label" for="sample3">Ansprech Partner...</label>
  </div>


<!-- Textfield with Floating Label -->

  <div class="mdl-textfield mdl-js-textfield mdl-textfield--floating-label">
    <input class="mdl-textfield__input" type="text" id="sample3" name="praktika">
    <label class="mdl-textfield__label" for="sample3">Praktika...</label>
  </div>

  <a></a><br>


<button class="mdl-button mdl-js-button mdl-button--raised mdl-js-ripple-effect mdl-button--accent" type="submit" id="submit" name="submit">
  Bearbeitung speichern
</button>

</form>

我不知道我在这里做错了什么，因为我没有得到500错误。

如果你能帮助我，我会很高兴。

亲切的问候，

Yan Malinovskiy

Php用户id更新mysql表

0 个答案: