Question

我收到了常见的DRF超链接模型详细信息错误，我想了解它的含义，所以我不再理解它。

观点如下：

import json
import time

from django.http import JsonResponse
from django.contrib.auth.models import User
from rest_framework import serializers, viewsets

from utils.general import unpack_request_body
from .models import Restaurant


#------------------------------------------------------------------------------------

class RestaurantSerializer(serializers.HyperlinkedModelSerializer):
    # answered by bovenson:
    #   https://stackoverflow.com/questions/20550598/django-rest-framework-could-not-resolve-url-for-hyperlinked-relationship-using
    # what just happened here? idk what HyperlinkedIdentityField does
    url = serializers.HyperlinkedIdentityField(view_name="restaurant:restaurant-detail")
    class Meta:
        model = Restaurant
        fields = '__all__'


class RestaurantViewSet(viewsets.ModelViewSet):
    queryset = Restaurant.objects.all()
    serializer_class = RestaurantSerializer

#------------------------------------------------------------------------------------

def find_restaurant_owned_by_a_username(username):
    try:
        user = User.objects.get(username=username)
    except:
        return None
    restaurants_owned = user.restaurants.all()
    if restaurants_owned:
        return restaurants_owned[0]
    else:
        return None

def restaurants_owned_by_this_username(request):
    """ for now only returns one restaurant """
    # TODO: will need to support multiple restaurants owned by one user in the future
    if request.method == "POST":
        body = unpack_request_body(request)
        username = body['username']
        restaurant_owned = find_restaurant_owned_by_a_username(username)
        if restaurant_owned:
            serializer =  RestaurantSerializer(restaurant_owned, context={'request': request})
            return JsonResponse({'result': serializer.data})
        else:
            return JsonResponse({'result': None})
    else:
        error_message = "This method only responds to POST"
        print(error_message)
        return JsonResponse({'error': error_message})

网址：

urlpatterns = [
    ...
    url(r'^api/restaurants-owned', csrf_exempt(views.restaurants_owned_by_this_username), name="restaurants-owned"),
]

models.py：

from django.contrib.auth.models import User


class Restaurant(models.Model):
    name = models.CharField(max_length=250, null=False, blank=False)
    phone = models.CharField(max_length=12)
    owner = models.ForeignKey(User, models.SET_NULL, related_name="restaurants", null=True, blank=True)

    address1 = models.CharField(max_length=250, null=False, blank=False)
    address2 = models.CharField(max_length=250, null=True, blank=True)
    city = models.CharField(max_length=250, null=False, blank=False)
    state = models.CharField(max_length=2, null=False, blank=False)
    zip_code = models.CharField(max_length=5, null=False, blank=False)

    lat = models.DecimalField(max_digits=10, decimal_places=7, null=True, blank=True)
    lng = models.DecimalField(max_digits=10, decimal_places=7, null=True, blank=True)

我现在点击端点，如POST http://localhost:8000/api/restaurants-owned/ {"username": "codyc4321"}

我得到了

django.core.exceptions.ImproperlyConfigured: Could not resolve URL for hyperlinked relationship using view name "user-detail". You may have failed to include the related model in your API, or incorrectly configured the `lookup_field` attribute on this field.

我一直在查找此错误消息，并在阅读完＆＃34;解决＆＃34;它，仍然不明白。人们似乎并没有解释它的含义。我不想要用户详细信息视图，我只将用户作为拥有该餐厅的外键。正如views.py所示，我解决了这个错误一次并且不了解它是如何工作的。

如何在将来停止此错误消息以及Django试图用它来说什么？

Django错误`django.core.exceptions.ImproperlyConfigured：无法使用视图名称解析超链接关系的URL＆＃34; user-detail＆＃34;`

0 个答案: