Question

import numpy as np
from scipy import interpolate
from scipy.interpolate import griddata
import itertools
from scipy.optimize import curve_fit
import matplotlib.pyplot as plt
import scipy.interpolate
import numpy as np, pylab
import os
from numpy import split


with open('zzz.txt') as fp:
    for line in fp:
        line = (line.split('=')[1].strip().split(','))
        line = list(map(float, line))
        print (line)


tck = interpolate.bisplrep(xx, yy, zz, s=0)

def givemeTL(X2,Y2):
    return interpolate.bisplev(X2,Y2,tck)

文件（zzz.txt）包括：

xx = 0.15, 0.2, 0.25, 0.3, 0.35, 0.4, 0.45, 0.5, 0.55 
yy = 0.01, 0.02, 0.03, 0.04, 0.05, 0.06, 0.07, 0.08, 0.09
zz = 0.75, 0.81, 0.83, 1.00, 0.92, 0.91, 0.745, 0.805, 0.82

我一直在收到错误 ValueError：无法将字符串转换为float：'xx = 0.15'

我每次都遇到这个问题，调用值是运行代码的一部分。但每次我改变调用方法时它都会给我错误。我该如何解决？最诚挚的问候

Answer 1

data = {}
with open('zzz.txt') as fp:
    for line in fp:
        var, values = list(map(str.strip, line.split('=')))
        values = list(map(float, values.split(',')))
        data[var] = values

Answer 2

我不会创建变量xx但我会用data['xx']创建字典 - 这是首选方法。

data = {} # dict for data from file

with open('zzz.txt') as fp:

    for line in fp:
        variable, numbers = line.split('=')

        variable = variable.strip()

        numbers = numbers.split(',')
        numbers = list(map(float, numbers))

        data[variable] = numbers

之后，您可以xx作为data['xx']

print(data['xx'])

或者您可以分配给变量

xx = data['xx']

您可以使用data[variable] = numbers而不是globals()[variable] = numbers，而不是xx而是变量xx = data['xx']，但人们说它不是首选方法。

从文件中调用值并使用Python运行代码

2 个答案: