根据Object中的密钥长度/计数对对象数组进行排序

Question

考虑json格式的对象数组，如下所示，

[
    {_id: "acd", employee: "jack"},
    {_id: "sdd", employee: "Monica", timeTaken: 0.6},
    {_id: "eee", employee: "Rose", timeTaken: 0.6, task: "GST"},
]

我很想简单地根据对象中的键数对对象数组进行排序。如果对象具有最大数量的键，则它必须位于顶部。

预期结果如下，

[       
    {_id: "eee", employee: "Monica", timeTaken: 0.6, task: "GST"},
    {_id: "sdd", employee: "Monica", timeTaken: 0.6},
    {_id: "acd", employee: "jack"},
]

任何帮助都将受到高度赞赏：）

Answer 1

使用sort根据对象中的键数对对象数组进行排序。

＆＃13;

＆＃13;

var arr = [
    {_id: "acd", employee: "jack"},
    {_id: "sdd", employee: "Monica", timeTaken: 0.6},
    {_id: "eee", employee: "Rose", timeTaken: 0.6, task: "GST"},
];

arr.sort(function(a,b){
  return Object.keys(b).length - Object.keys(a).length;
});
console.log(arr);

＆＃13;

＆＃13;

＆＃13;