Question

我们希望获得SQL Server实例级别（包括所有数据库）的每种对象类型的总数。

E.g。

Stored Procedures
Views
Tables
Constraints
Jobs
Linked Servers
Replication

此代码返回数据库级别的计数;如何更改此代码以显示实例级别的计数？

WITH objs AS
(
    SELECT 
        type_desc AS Object_Type,
        COUNT(*) AS Object_Count, 1 AS JoinColumn
    FROM 
        sys.objects
    --exclude internal tables, service queues, and system tables
    WHERE 
        TYPE NOT IN ('IT', 'S', 'SQ')
    GROUP BY 
        type_desc
),
tots AS
(
    SELECT COUNT(*) AS Type_Count, 1 AS JoinColumn
    FROM sys.objects
    WHERE TYPE NOT IN ('IT', 'S', 'SQ')
)
SELECT 
    Object_Type, Object_Count, Type_Count,
    CAST((Object_Count * 1.0) / Type_Count * 100 AS INT) AS Type_Pct
FROM objs o
JOIN tots s ON o.JoinColumn = s.JoinColumn
ORDER BY Object_Type;

此致

Answer 1

以下是使用动态SQL和游标迭代服务器上所有用户数据库的示例。

SET NOCOUNT ON;
DECLARE @DatabaseCounts TABLE(
       Object_Type nvarchar(60)
     , Object_Count INT
     );

DECLARE
      @DatabaseName sysname
    , @SQL nvarchar(MAX);

DECLARE Databases CURSOR LOCAL FAST_FORWARD FOR
    SELECT name 
    FROM sys.databases
    WHERE
        name NOT IN(N'master',N'model',N'tempdb',N'msdb',N'SSISDB',N'distribution');

OPEN Databases;
WHILE 1 = 1
BEGIN
    FETCH NEXT FROM Databases INTO @DatabaseName;
    IF @@FETCH_STATUS = -1 BREAK;
    SET @SQL = N'
USE ' + QUOTENAME(@DatabaseName) + N';
    SELECT
          type_desc AS Object_Type
        , COUNT(*) AS Object_Count
    FROM sys.objects
    --exclude internal tables, service queues, and system tables
    WHERE TYPE NOT IN (''IT'', ''S'', ''SQ'')
    GROUP BY type_desc
';
    INSERT INTO @DatabaseCounts
        EXEC sp_executesql @SQL;
END;
CLOSE Databases;
DEALLOCATE Databases;

WITH
     instance_counts1 AS (
        SELECT
              Object_Type
            , SUM(Object_Count) AS Object_Count
        FROM @DatabaseCounts
        GROUP BY Object_Type
    )
    , instance_counts2 AS (
        SELECT
              Object_Type
            , Object_Count
            , (SELECT SUM(Object_Count) FROM instance_counts1) AS Type_Count
        FROM instance_counts1
    )
SELECT
      Object_Type
    , Object_Count
    , Type_Count
    , CAST(ROUND(Object_Count * 100.0 / Type_Count, 0) AS INT) AS Type_Pct
FROM instance_counts2;

SQL Server - 在实例级别计算每个对象

1 个答案: